A1083 List Grades (25 分)

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Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:
Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2
where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade‘s interval. It is guaranteed that all the grades are distinct.

Output Specification:
For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student‘s name and ID, separated by one space. If there is no student‘s grade in that interval, output NONE instead.

Sample Input 1:
4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100
Sample Output 1:
Mike CS991301
Mary EE990830
Joe Math990112
Sample Input 2:
2
Jean AA980920 60
Ann CS01 80
90 95
Sample Output 2:
NONE

开始技术总结：

• 第一点就是初始化数组或是结构体的时候，大小要用常量，不能够使用输入量初始化

• 还有就是中文的括号注意一点

• 参考代码：

#define _CRT_SECURE_NO_WARNINGS
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
using namespace std;
const int MAXN = 50;
struct Student {
    char ID[11];
    char name[11];
    int grade;
}student[MAXN];

bool cmp(Student a, Student b) {
    if (a.grade != b.grade) return a.grade > b.grade;
}

int main(){

    int grade1, grade2;
    int N;
    scanf("%d", &N);
    for (int i = 0; i < N; i++) {
        scanf("%s%s%d", student[i].name, student[i].ID, &student[i].grade);
    }
    scanf("%d%d", &grade1, &grade2);
    sort(student, student + N, cmp);
    int flag = 0;//用来标记是否又符合条件的同学，0表示没有
    for (int j = 0; j < N; j++) {
        if (student[j].grade <= grade2 && student[j].grade >= grade1) {
            printf("%s %s\n", student[j].name, student[j].ID);
            flag = 1;
        }
    }
    if (flag == 0) {
        printf("NONE");
    }
    system("pause");
    return 0;
}

A1083 List Grades (25 分)

标签：strong   tin   aries   scanf   hat   pause   more   使用   spec   

原文地址：https://www.cnblogs.com/tsruixi/p/11553140.html