标签：icp line har pac orm round -- silver enter
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it‘s easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
For each test case you should output the sum of A and B in one line, with the same format as the input.
3.2.1 10.16.27
14.1.28
题意：
17个Sickle对换一个Galleon，29个Knut对换一个Sickle。根据Galleon.Sickle.Knut的方式相加A和B
分析：把A和B都化为Knut的形式，然后相加，最后转换为Galleon.Sickle.Knut的形式。
AC代码：
#include<iostream> using namespace std; int a1,b1,c1,a2,b2,c2; int main(){ scanf("%d.%d.%d %d.%d.%d",&a1,&b1,&c1,&a2,&b2,&c2); a1+=a2; b1+=b2; c1+=c2; int x=c1/29; c1-=x*29; b1+=x; x=b1/17; b1-=x*17; a1+=x; printf("%d.%d.%d",a1,b1,c1); return 0; }
PAT 甲级 1058 A+B in Hogwarts (20 分) （简单题）
标签：icp line har pac orm round -- silver enter
原文地址：https://www.cnblogs.com/caiyishuai/p/11557934.html
