爬虫技术：爬取淘宝美食数据：崔庆才思路

import random
import re
import time
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC


driver = webdriver.Chrome()

def search():
    """执行后跳转到登录界面--手动登录，且wait容易引起超时错误，因此需要捕捉"""
    try:
        driver.get("https://www.taobao.com/")
        # 获取输入框
        input = WebDriverWait(driver, 15).until(
            EC.presence_of_element_located((By.CSS_SELECTOR, "#q"))
        )
        # 获取搜索按钮，TODO 为什么不用id选择器呢？
        submit = WebDriverWait(driver,15).until(EC.element_to_be_clickable((By.CSS_SELECTOR,"#J_TSearchForm > div.search-button > button")))
        input.send_keys("美食")
        time.sleep(1)
        submit.click()
        # 获取全部页数
        total = WebDriverWait(driver,15).until(EC.presence_of_element_located((By.CSS_SELECTOR,"#mainsrp-pager > div > div > div > div.total")))
        return total.text
    except TimeoutError:
        return search()

def next_page(page):
    try:
        # 获取第几页输入框
        input = WebDriverWait(driver, 15).until(
            EC.presence_of_element_located((By.CSS_SELECTOR, "#mainsrp-pager > div > div > div > div.form > input"))
        )
        # 获取确定按钮
        submit = WebDriverWait(driver,15).until(EC.element_to_be_clickable((By.CSS_SELECTOR,"#mainsrp-pager > div > div > div > div.form > span.btn.J_Submit")))
        input.clear()
        input.send_keys(page)
        # time.sleep(1)  # 1.解决方式：翻页翻到34页，出现滑块验证，系统检测出来了，是自动化操作，时间不能固定
        second = random.randint(1,6) # 设置随机时间后，第一次就要进行人工验证，# TODO 淘宝验证出selenium的方式是啥？
        time.sleep(second)
        submit.click()
        # 判断条件:当前高亮文本的内容和页码参数是否相同
        WebDriverWait(driver,15).until(EC.text_to_be_present_in_element((By.CSS_SELECTOR,"#mainsrp-pager > div > div > div > ul > li.item.active > span"),str(page)))
    except TimeoutError:
        return next_page(page)
    


if __name__ == ‘__main__‘:
    total = search()  # 共 100 页，
    pattern = re.compile("(\d+)",re.S)
    total_page = re.search(pattern,total)
    total_page = int(total_page.group(1))
    for i in range(2, total_page + 1):
        next_page(i)