标签:++ opencv 平面 original sam next pre 添加 core
#include "opencv2/core/core.hpp" #include "opencv2/highgui/highgui.hpp" #include "opencv2/imgproc/imgproc.hpp" #include "opencv2/features2d/features2d.hpp" //需要添加该头文件 #include <iostream> #include "Math.h"27 using namespace cv; using namespace std; int main() { float angle = 0; Mat image(200, 400, CV_8UC3, Scalar(0)); RotatedRect originalRect; Point2f vertices[4]; vector<Point2f> vertVect; RotatedRect calculatedRect; while (waitKey(5000) != 27) { // Create a rectangle, rotating it by 10 degrees more each time. originalRect = RotatedRect(Point2f(100, 100), Size2f(100, 50), angle); // Convert the rectangle to a vector of points for minAreaRect to use. // Also move the points to the right, so that the two rectangles aren‘t // in the same place. originalRect.points(vertices); for (int i = 0; i < 4; i++) { vertVect.push_back(vertices[i] + Point2f(200, 0)); } // Get minAreaRect to find a rectangle that encloses the points. This // should have the exact same orientation as our original rectangle. calculatedRect = minAreaRect(vertVect); // Draw the original rectangle, and the one given by minAreaRect. for (int i = 0; i < 4; i++) { line(image, vertices[i], vertices[(i + 1) % 4], Scalar(0, 255, 0)); line(image, vertVect[i], vertVect[(i + 1) % 4], Scalar(255, 0, 0)); } imshow("rectangles", image); // Print the angle values. printf("---\n"); printf("Original angle: %7.2f\n", angle); printf("Angle given by minAreaRect: %7.2f\n", calculatedRect.angle); printf("---\n"); // Reset everything for the next frame. image = Mat(200, 400, CV_8UC3, Scalar(0)); vertVect.clear(); angle += 10; } return 0; }
[opencv]利用minAreaRect计算平面矩形的旋转角度
标签:++ opencv 平面 original sam next pre 添加 core
原文地址:https://www.cnblogs.com/lx17746071609/p/11577382.html