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Fibonacci Again

时间:2014-10-27 17:30:21      阅读:151      评论:0      收藏:0      [点我收藏+]

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Problem Description

There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).

 

Input

Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).

 

Output

Print the word "yes" if 3 divide evenly into F(n).

Print the word "no" if not.

 

Sample Input

0

1

2

3

4

5

 

Sample Output

no

no

yes

no

no

no

 

 1 #include <stdio.h>
 2  
 3 int calculate_Fn(int number);
 4  
 5 int main(){
 6     int number;
 7      
 8     while((scanf("%d",&number))!=EOF){
 9         if(calculate_Fn(number)==0)
10             printf("yes\n");
11          
12         else
13             printf("no\n");
14     }
15     return 0;
16 }
17  
18 int calculate_Fn(int number){
19     int i;
20     int result;
21     int temp;
22     int a=7;
23     int b=11;
24      
25     if(number==0)
26         return a;
27          
28     else if(number==1)
29         return b;
30          
31     for(i=2;i<=number;i++){
32         result=(a%3+b%3)%3;
33          
34         temp=b;
35         b=result;
36         a=temp;
37     }
38      
39     return result;
40 }

 

Fibonacci Again

标签:des   style   blog   io   color   ar   for   sp   div   

原文地址:http://www.cnblogs.com/zqxLonely/p/4054492.html

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