标签:blog class code c color int
Given two binary strings, return their sum (also a binary string).
For example, a = "11"
b = "1"
Return
"100"
.
string 的操作,短string补位。两个“0”会输出一个“00”,要特殊处理,plus如果最后为“1”,要补上。
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76 |
class
Solution { public : char
getBit(string s, int
n) { if (n >= s.length()) { return
‘0‘ ; } else { return
s[n]; } } char
Add( char
a, char
b, char
c, char
&remain) { if (a == ‘1‘
&& b== ‘1‘
&& c== ‘1‘ ) { remain = ‘1‘ ; return
‘1‘ ; } if ((a == ‘1‘
&& b == ‘1‘ ) || (a == ‘1‘
&& c == ‘1‘ ) || (c == ‘1‘
&& b == ‘1‘ )) { remain = ‘0‘ ; return
‘1‘ ; } if (a == ‘0‘
&& b == ‘0‘
&& c == ‘0‘ ) { remain = ‘0‘ ; return
‘0‘ ; } remain = ‘1‘ ; return
‘0‘ ; } string addBinary(string a, string b) { int
n1 = a.length(); int
n2 = b.length(); int
n = n1; if (n1 > n2) { n = n1; b = string(n1-n2, ‘0‘ ) + b; } else
if (n1 < n2) { n = n2; a = string(n2-n1, ‘0‘ ) + a; } if (a== "0"
&& b == "0" ) return
"0" ; string sum = "FIRST" ; char
plus = ‘0‘ ; char
remain = ‘0‘ ; for ( int
i = n-1; i>=0 ;i--) { plus = Add(a[i],b[i],plus, remain); if (sum == "FIRST" ) { sum = string (1, remain); } else { sum = string(1,remain) + sum; } } if (plus == ‘1‘ ) { sum = string(1,plus) + sum; } return
sum; } }; |
[LeetCode] [Add Binary 2012-04-02 ],布布扣,bubuko.com
[LeetCode] [Add Binary 2012-04-02 ]
标签:blog class code c color int
原文地址:http://www.cnblogs.com/xxiao1119/p/3729823.html