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300. Longest Increasing Subsequence

时间:2019-09-28 11:16:10      阅读:106      评论:0      收藏:0      [点我收藏+]

标签:col   span   技术   seq   algo   src   lis   long   lan   

Given an unsorted array of integers, find the length of longest increasing subsequence.

Example:

Input: [10,9,2,5,3,7,101,18]
Output: 4 
Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4. 

Note:

  • There may be more than one LIS combination, it is only necessary for you to return the length.
  • Your algorithm should run in O(n2) complexity.

Follow up: Could you improve it to O(n log n) time complexity?

class Solution {
    public int lengthOfLIS(int[] nums) {
        int l = nums.length;
        if(l == 0) return 0;
        int[] f = new int[l];
        int res = 1;
        Arrays.fill(f,1);
        for(int j = 1; j < l; j++){
            for(int i = 0; i < j; i++){
                if(nums[j] > nums[i]){
                    f[j] = Math.max(f[j], f[i] + 1);
                }
            }
            res = Math.max(res, f[j]);
        }
        return res;
    }
}

技术图片

 

300. Longest Increasing Subsequence

标签:col   span   技术   seq   algo   src   lis   long   lan   

原文地址:https://www.cnblogs.com/wentiliangkaihua/p/11601660.html

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