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LeetCode_104. Maximum Depth of Binary Tree

时间:2019-09-29 15:39:53      阅读:112      评论:0      收藏:0      [点我收藏+]

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104. Maximum Depth of Binary Tree

Easy

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Note: A leaf is a node with no children.

Example:

Given binary tree [3,9,20,null,null,15,7],

    3
   /   9  20
    /     15   7

return its depth = 3.

 

package leetcode.easy;

public class MaximumDepthOfBinaryTree {
	@org.junit.Test
	public void test() {
		TreeNode tn11 = new TreeNode(3);
		TreeNode tn21 = new TreeNode(9);
		TreeNode tn22 = new TreeNode(20);
		TreeNode tn33 = new TreeNode(15);
		TreeNode tn34 = new TreeNode(7);
		tn11.left = tn21;
		tn11.right = tn22;
		tn21.left = null;
		tn21.right = null;
		tn22.left = tn33;
		tn22.right = tn34;
		tn33.left = null;
		tn33.right = null;
		tn34.left = null;
		tn34.right = null;
		System.out.println(maxDepth(tn11));
	}

	public int maxDepth(TreeNode root) {
		if (root == null) {
			return 0;
		}
		return Math.max(maxDepth(root.left), maxDepth(root.right)) + 1;
	}
}

 

LeetCode_104. Maximum Depth of Binary Tree

标签:etc   down   print   turn   number   bsp   treenode   public   des   

原文地址:https://www.cnblogs.com/denggelin/p/11608134.html

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