标签：sed int 斐波那契数 斐波那契数列 img code div print show
#-----列表生成器-----
1 a = [x*2 for x in range(10)] 2 print(a,type(a)) #[0, 2, 4, 6, 8, 10, 12, 14, 16, 18] <class ‘list‘> 3 4 def f(n): 5 return n**3 6 7 a = [f(x) for x in range(10)] 8 print(a,type(a)) #[0, 1, 8, 27, 64, 125, 216, 343, 512, 729] <class ‘list‘>
#-----简单赋值方式
1 t = (12,45) 2 a,b = t 3 print(a)#12 4 print(b)#45
#----生成器(生成器就是可迭代对象)-----
1 s = (x*2 for x in range(10)) 2 for i in s: 3 print(i,end=" ") # 0 2 4 6 8 10 12 14 16 18 4 5 #可迭代对象 ：内部有iter 方法 6 a = (1,2,3,5) 7 a.__iter__() 8 b = [2,3,4,5] 9 b.__iter__() 10 c = {"a":"d","g":"r"} 11 c.__iter__() 12 e = set(a) 13 print(e,type(e)) 14 e.__iter__()
#-----yield关键字生成斐波那契数列
1 def fib(max): 2 n,before,after = 0,0,1 3 while n < max: 4 yield after 5 before,after = after,before+after 6 n += 1 7 8 g = fib(6) 9 for i in g: 10 print(i)
#-----yield 使用
1 def bar(): 2 print("ok1") 3 str1 = yield 1 4 print(str1) 5 6 print("ok2") 7 str2 = yield 2 8 print(str2) 9 b = bar() 10 next(b) 11 ret = b.send("ee") 12 print(ret)
#-----还可通过yield实现在单线程的情况下实现并发运算的效果
1 import time 2 3 def tourist(name): 4 print("%s 开始吃包子" % name) 5 while True: 6 baozi = yield #生成器函数(generator) 7 print("%s吃了第%s个" % (name, baozi)) 8 9 def cook(name): 10 c1 = tourist("A") 11 c2 = tourist("B") 12 c1.__next__() 13 c2.__next__() 14 print("%s开始做包子了" % name) 15 for i in range(1,10): 16 time.sleep(0.2) 17 c1.send(i) 18 c2.send(i) 19 cook("dream")
#-----迭代器-----
1、有iter方法
2、有next方法
1 a = ["dream","rise","happy"] 2 d = iter(a) #<list_iterator object at 0x000001E01BFADA90> 3 print(d) 4 print(a.__iter__())#<list_iterator object at 0x00000258F8392668>
标签：sed int 斐波那契数 斐波那契数列 img code div print show
原文地址：https://www.cnblogs.com/rise-home/p/11612358.html
