LintCode入门题目

class Solution {
public:
    /**
     * @param number: A 3-digit number.
     * @return: Reversed number.
     */
    int reverseInteger(int number) {
        // write your code here
        int a=0,b=0,c=0,reverse=0;
        a = number/100; //百位
        b = (number-a*100)/10; //十位
        c = number-a*100-b*10; //个位
        if(a!=0)
        reverse += a;
        if(b!=0)
        reverse += b*10;
        if(c!=0)
        reverse += c*100;
        return reverse;
        }
};