标签：into tco orm 语句 nis for record ids order
Table: Teams
+---------------+----------+
| Column Name | Type |
+---------------+----------+
| team_id | int |
| team_name | varchar |
+---------------+----------+
team_id is the primary key of this table.
Each row of this table represents a single football team.
Table: Matches
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| match_id | int |
| host_team | int |
| guest_team | int |
| host_goals | int |
| guest_goals | int |
+---------------+---------+
match_id is the primary key of this table.
Each row is a record of a finished match between two different teams.
Teams host_team and guest_team are represented by their IDs in the teams table (team_id) and they scored host_goals and guest_goals goals respectively.
You would like to compute the scores of all teams after all matches. Points are awarded as follows:
Write an SQL query that selects the team_id, team_name and num_points of each team in the tournament after all described matches. Result table should be ordered by num_points (decreasing order). In case of a tie, order the records by team_id (increasing order).
The query result format is in the following example:
Teams table:
+-----------+--------------+
| team_id | team_name |
+-----------+--------------+
| 10 | Leetcode FC |
| 20 | NewYork FC |
| 30 | Atlanta FC |
| 40 | Chicago FC |
| 50 | Toronto FC |
+-----------+--------------+
Matches table:
+------------+--------------+---------------+-------------+--------------+
| match_id | host_team | guest_team | host_goals | guest_goals |
+------------+--------------+---------------+-------------+--------------+
| 1 | 10 | 20 | 3 | 0 |
| 2 | 30 | 10 | 2 | 2 |
| 3 | 10 | 50 | 5 | 1 |
| 4 | 20 | 30 | 1 | 0 |
| 5 | 50 | 30 | 1 | 0 |
+------------+--------------+---------------+-------------+--------------+
Result table:
+------------+--------------+---------------+
| team_id | team_name | num_points |
+------------+--------------+---------------+
| 10 | Leetcode FC | 7 |
| 20 | NewYork FC | 3 |
| 50 | Toronto FC | 3 |
| 30 | Atlanta FC | 1 |
| 40 | Chicago FC | 0 |
+------------+--------------+---------------+
简要翻译：
两张表：队伍表和比赛表。统计队伍积分，胜3分，平1分，负0分，查询个队伍排名榜，查询结果先按积分降序，然后按team_id升序排列。
建表语句：
CREATE TABLE Teams (
team_id INT ,
team_name VARCHAR (20)
) ;
CREATE TABLE Matches (
match_id INT ,
host_team INT ,
guest_team INT ,
host_goals INT,
guest_goals INT
) ;
INSERT INTO Teams (team_id, team_name)
VALUES
(10, ‘Leetcode FC‘) ;
INSERT INTO Teams (team_id, team_name)
VALUES
(20, ‘NewYork FC‘) ;
INSERT INTO Teams (team_id, team_name)
VALUES
(30, ‘Atlanta FC‘) ;
INSERT INTO Teams (team_id, team_name)
VALUES
(40, ‘Chicago FC‘) ;
INSERT INTO Teams (team_id, team_name)
VALUES
(50, ‘Toronto FC‘) ;
INSERT INTO Matches (
match_id,
host_team,
guest_team,
host_goals,
guest_goals
)
VALUES
(1, 10, 20, 3, 0) ;
INSERT INTO Matches (
match_id,
host_team,
guest_team,
host_goals,
guest_goals
)
VALUES
(2, 30, 10, 2, 2) ;
INSERT INTO Matches (
match_id,
host_team,
guest_team,
host_goals,
guest_goals
)
VALUES
(3, 10, 50, 5, 1) ;
INSERT INTO Matches (
match_id,
host_team,
guest_team,
host_goals,
guest_goals
)
VALUES
(4, 20, 30, 1, 0) ;
INSERT INTO Matches (
match_id,
host_team,
guest_team,
host_goals,
guest_goals
)
VALUES
(5, 50, 30, 1, 0) ;
SQL思路：
一、查询每场比赛各队伍得分：
# 作为主队的得分统计：
1 SELECT
2 team_id,
3 team_name,
4 IF(
5 host_goals > guest_goals,
6 3,
7 IF(host_goals = guest_goals, 1, 0)
8 ) AS points
9 FROM
10 teams,
11 matches
12 WHERE team_id = host_team;
#作为客队的得分统计
1 SELECT
2 team_id,
3 team_name,
4 IF(
5 host_goals > guest_goals,
6 0,
7 IF(host_goals = guest_goals, 1, 3)
8 ) AS points
9 FROM
10 teams,
11 matches
12 WHERE team_id = guest_team;
二、将上两张表union all ，然后分组聚合查询，然后发现少了没参赛队伍的积分。因此需要left join 。最终查询语句如下
1 SELECT
2 t.team_id,
3 t.team_name,
4 SUM(IFNULL(points,0)) AS num_points
5 FROM
6 teams t LEFT JOIN
7 (
8 SELECT
9 team_id,
10 team_name,
11 IF(
12 host_goals > guest_goals,
13 3,
14 IF(host_goals = guest_goals, 1, 0)
15 ) AS points
16 FROM
17 teams,
18 matches
19 WHERE team_id = host_team
20 UNION ALL
21 SELECT
22 team_id,
23 team_name,
24 IF(
25 host_goals > guest_goals,
26 0,
27 IF(host_goals = guest_goals, 1, 3)
28 ) AS points
29 FROM
30 teams,
31 matches
32 WHERE team_id = guest_team
33 )temp ON
34 t.team_id = temp.team_id
35 GROUP BY team_id
36 ORDER BY num_points DESC ,team_id ASC ;
LeetCode 1212. Team Scores in Football Tournament
标签：into tco orm 语句 nis for record ids order
原文地址：https://www.cnblogs.com/onePunchCoder/p/11619433.html
