标签：play   最小   wing   each   tun   std   call   beginning   codeforce   

链接:

https://codeforces.com/contest/1220/problem/C

题意:

Mike and Ann are sitting in the classroom. The lesson is boring, so they decided to play an interesting game. Fortunately, all they need to play this game is a string s and a number k (0≤k<|s|).

At the beginning of the game, players are given a substring of s with left border l and right border r, both equal to k (i.e. initially l=r=k). Then players start to make moves one by one, according to the following rules:

A player chooses l′ and r′ so that l′≤l, r′≥r and s[l′,r′] is lexicographically less than s[l,r]. Then the player changes l and r in this way: l:=l′, r:=r′.
Ann moves first.
The player, that can‘t make a move loses.
Recall that a substring s[l,r] (l≤r) of a string s is a continuous segment of letters from s that starts at position l and ends at position r. For example, "ehn" is a substring (s[3,5]) of "aaaehnsvz" and "ahz" is not.

Mike and Ann were playing so enthusiastically that they did not notice the teacher approached them. Surprisingly, the teacher didn‘t scold them, instead of that he said, that he can figure out the winner of the game before it starts, even if he knows only s and k.

Unfortunately, Mike and Ann are not so keen in the game theory, so they ask you to write a program, that takes s and determines the winner for all possible k.

思路:

将l‘扩展到右边最小的位置, 就可以保证下一次没有操作余地.
同时l的左边没有更小的就输了.

代码:

#include <bits/stdc++.h>
using namespace std;
const int MAXN = 5e5+10;

char s[MAXN];

int main()
{
    cin >> s;
    int len = strlen(s);
    int minv = 25;
    for (int i = 0;i < len;i++)
    {
        if (s[i]-'a' > minv)
            puts("Ann");
        else
            puts("Mike");
        if (s[i]-'a' < minv)
            minv = s[i]-'a';
    }
    
    return 0;
}

Codeforces Round #586 (Div. 1 + Div. 2) C. Substring Game in the Lesson

标签：play   最小   wing   each   tun   std   call   beginning   codeforce   

原文地址：https://www.cnblogs.com/YDDDD/p/11626658.html