标签:reac strlen class ace bool string amp getch ==
注意标记一个点后,fail树上的子节点都会被标记
跑spfa,dp也可以
#include<iostream> #include<cstdio> #include<string> #include<cstring> #include<algorithm> #include<cmath> #include<vector> #include <set> #include <queue> #define ll long long #define ld long double #define lson l,m,rt<<1 #define pi acos(-1) #define rson m+1,r,rt<<1|1 #define fo(i,l,r) for(int i = l;i <= r;i++) #define fd(i,l,r) for(int i = r;i >= l;i--) #define mem(x) memset(x,0,sizeof(x)) #define eps 1e-8 using namespace std; const int maxn = 50050; const ll inf = 1e9; const ll mod = 998244353; ll read() { ll x=0,f=1; char ch=getchar(); while(!(ch>=‘0‘&&ch<=‘9‘)) { if(ch==‘-‘)f=-1; ch=getchar(); }; while(ch>=‘0‘&&ch<=‘9‘) { x=x*10+(ch-‘0‘); ch=getchar(); }; return x*f; } struct Trie{ int nxt[maxn][55],fail[maxn],end[maxn]; int root,L; int newnode(){ for(int i = 0;i < 55;i++) nxt[L][i] = -1; end[L++]=0; return L-1; } void init(){ L = 0; root = newnode(); } void insert(char buf[],bool bj){ int len = strlen(buf); int now = root; for(int i = 0;i < len;i++){ if(nxt[now][buf[i]]==-1) nxt[now][buf[i]] = newnode(); now = nxt[now][buf[i]]; } if(bj)end[now]++; } void build(){ queue<int> Q; fail[root] = root; for(int i = 0;i < 55;i++) { if (nxt[root][i] == -1) { nxt[root][i] = root; } else { fail[nxt[root][i]] = root; Q.push((nxt[root][i])); } } while(!Q.empty()){ int now = Q.front(); Q.pop(); if(end[fail[now]]) end[now]=1; for(int i = 0;i < 55;i++){ if(nxt[now][i]==-1) { nxt[now][i] = nxt[fail[now]][i]; }else{ fail[nxt[now][i]] = nxt[fail[now]][i]; Q.push(nxt[now][i]); } } } } }ac; int n,m,k; double xx[maxn],yy[maxn]; char s[25]; struct dat{ int u; int v; double dis; }now,nxt; vector<dat> g[1050][55]; double d[1050][55]; bool vis[1050][55]; double ans; void spfa(){ queue<dat> q; fo(i,0,ac.L-1){ fo(j,1,n){ vis[i][j]=false; d[i][j]=-100.0; } } now.u = ac.nxt[0][1];now.v=1; q.push(now); vis[now.u][1]=true;d[now.u][1]=0.0; while(!q.empty()){ now = q.front(); q.pop(); for(dat t:g[now.u][now.v]){ if(d[t.u][t.v]<0||(d[now.u][now.v]+t.dis<d[t.u][t.v])){ d[t.u][t.v] = d[now.u][now.v]+t.dis; if(!vis[t.u][t.v]){ vis[t.u][t.v]=true; q.push(t); } } } if(now.v==n){ if(ans<0||d[now.u][now.v] <ans)ans=d[now.u][now.v]; } vis[now.u][now.v]=false; } } int main() { while(true){ ac.init(); ans=-1.0; n=read();m=read(); if(!n&&!m)break; fo(i,1,n){ xx[i]=read();yy[i]=read(); } fo(i,1,m){ k=read(); int t; fo(j,1,k){ t=read(); s[j-1]=t; } s[k]=‘\0‘; ac.insert(s,true); } ac.build(); int v; fo(i,0,ac.L-1){ fo(j,1,n) g[i][j].clear(); fo(j,1,n){ v=ac.nxt[i][j]; if(ac.end[v])continue; now.u = v; now.v = j; fo(k,1,n){ if(k>=j)continue; now.dis = sqrt((xx[j]-xx[k])*(xx[j]-xx[k]) + (yy[j]-yy[k])*(yy[j]-yy[k])); g[i][k].push_back(now); } } } spfa(); if(fabs(ans)<eps)ans=0; if(ans<-eps)puts("Can not be reached!"); else printf("%.2f\n",ans); } return 0; }
标签:reac strlen class ace bool string amp getch ==
原文地址:https://www.cnblogs.com/hyfer/p/11664311.html