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[LC] 53. Maximum Subarray

时间:2019-10-13 23:34:58      阅读:112      评论:0      收藏:0      [点我收藏+]

标签:sel   nta   xpl   contain   subarray   ace   return   code   self   

Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.

Example:

Input: [-2,1,-3,4,-1,2,1,-5,4],
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.

Time:O(N)
Space:O(N)

 1 class Solution:
 2     def maxSubArray(self, nums: List[int]) -> int:
 3         if nums is None or len(nums) == 0:
 4             return
 5         
 6         sum_arr = [0] * len(nums)
 7         sum_arr[0] = nums[0]
 8         max_res = nums[0]
 9         for i in range(1, len(nums)):
10             if sum_arr[i - 1] > 0:
11                 sum_arr[i] = nums[i] + sum_arr[i - 1]
12             else:
13                 sum_arr[i] = nums[i]
14             max_res = max(max_res, sum_arr[i])
15         return max_res

 

[LC] 53. Maximum Subarray

标签:sel   nta   xpl   contain   subarray   ace   return   code   self   

原文地址:https://www.cnblogs.com/xuanlu/p/11668980.html

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