参考代码1011-1020

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     int a,b;
 6     int c; 
 7     cin>>a>>b;
 8     c=(a*10+b)/19; 
 9     cout<<c<<endl;
10     return 0;
11  }

 1 #include <bits/stdc++.h>           
 2 using namespace std;                
 3 int main()                      
 4 {   
 5     int n;
 6     cin>>n;
 7     cout<<n<<endl;
 8     n+=25;
 9     cout<<n<<endl;
10     n+=25;
11     cout<<n<<endl;
12     return 0;         
13   } 

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     int m,n;
 6     cin>>m;
 7     n=(m/3)*4 +m%3;
 8     cout<<n;
 9     return 0;
10  } 

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     int a,b;
 6     int c; 
 7     cin>>a>>b;
 8     c=(a*b)/2; 
 9     cout<<c<<endl;
10     return 0;
11  }

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     int a;
 6     int c; 
 7     cin>>a;
 8     c=6*(a*a); 
 9     cout<<c<<endl;
10     return 0;
11  }

 1 #include <bits/stdc++.h>           
 2 using namespace std;                
 3 int main()                      
 4 {   
 5     int a,b;
 6     cin>>a>>b;
 7     double c;
 8     c=a/(b*1.0);
 9 //    cout<<fixed<<setprecision(9)<<c<<endl;
10     printf("%.9lf\n",c);
11     return 0;         
12   }

 1 #include <bits/stdc++.h>           
 2 using namespace std;                
 3 int main()                      
 4 {   
 5     int a,b,c;
 6     cin>>a>>b>>c;
 7     double d;
 8     d=(a+b+c)/3.0;
 9     printf("%.1lf\n",d);
10     return 0;         
11   }

 1 #include <bits/stdc++.h>           
 2 using namespace std;                
 3 int main()                      
 4 {   //C = 5*(F-32)/9 
 5     double f,c;
 6     cin>>f;
 7 
 8     c=5*(f-32)/9.0;
 9     printf("%.5lf\n",c);
10     return 0;         
11   } 

#include <bits/stdc++.h>           
using namespace std;                
int main()                      
{   int a,b,c; 
    double s;
    cin>>a>>b>>c;
    s=(a+b)*c/2.0;
    printf("%.2lf\n",s);
    return 0;         
  } 

 1 #include <bits/stdc++.h>           
 2 using namespace std;                
 3 int main()                      
 4 {   
 5     double a;
 6     int b;
 7     cin>>a>>b;
 8     a=a*pow(10,b);
 9     a=(int)(a+0.5);
10     a=a*1.0/pow(10,b);
11     printf("%0.*lf\n",b,a);
12     return 0;
13   }