标签：self rmi ring set purpose span ascii return lin
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
Note: For the purpose of this problem, we define empty string as valid palindrome.
Example 1:
Input: "A man, a plan, a canal: Panama" Output: true
Example 2:
Input: "race a car" Output: false
class Solution(object): def isPalindrome(self, s): """ :type s: str :rtype: bool """ if s is ‘‘: return True import string valid = set(string.ascii_letters + string.digits) s_cp = s[:].lower() left, right = 0, len(s) - 1 while left <= right: if s_cp[left] not in valid: left += 1 elif s_cp[right] not in valid: right -= 1 elif s_cp[left] != s_cp[right]: return False else: left += 1 right -= 1 return True
标签：self rmi ring set purpose span ascii return lin
原文地址：https://www.cnblogs.com/xuanlu/p/11711310.html
