LeetCode Add Binary

 1 public class Solution {
 2     public String addBinary(String a, String b) {
 3        
 4        int la=a.length();
 5        int lb=b.length();
 6        char[] chars=new char[Math.max(la,lb)+1];
 7        int flag=0;
 8        int lastA=la-1;
 9        int lastB=lb-1;
10        int c=0;
11        int currA,currB;
12        for (int i = chars.length-1; i >=0; i--) {
13                    currA=lastA>=0?a.charAt(lastA):‘0‘;
14                    currB=lastB>=0?b.charAt(lastB):‘0‘;
15                    c=currA-‘0‘+currB-‘0‘+flag;
16                    if (c==3) {
17                     chars[i]=‘1‘;
18                     flag=1;
19                 }else if (c==2) {
20                     chars[i]=‘0‘;
21                     flag=1;
22                 }else {
23                     chars[i]=(char) (‘0‘+c);
24                     flag=0;
25                 }
26                    lastA--;
27                    lastB--;
28        }
29        String string=new String(chars);
30        if (string.charAt(0)==‘0‘) {
31         return string.substring(1);
32     }
33        return string;
34     }
35 }