标签:line stdin dig 应该 return operator tchar oid char
已经很快了,oi基本够用了
template<typename xxx>void read(xxx &x)
{
x=0;int f=1;char c=getchar();
for(;c<'0'||c>'9';c=getchar()) if(c=='-') f=-1;
for(;c>='0'&&c<='9';c=getchar()) x=(x<<1)+(x<<3)+(c^48);
x*=f;
}
比基本版还快一些
template <typename _tp> inline _tp read(_tp&x){
char ch=getchar(),sgn=0;x=0;
while(ch^'-'&&!isdigit(ch))ch=getchar();if(ch=='-')ch=getchar(),sgn=1;
while(isdigit(ch))x=x*10+ch-'0',ch=getchar();if(sgn)x=-x;return x;
}
究极快速输入,应该不存在(时间上)卡这个输入的了(所以小心空间);
struct ios {
inline char gc(){
static const int IN_LEN=1<<18|1;
static char buf[IN_LEN],*s,*t;
return (s==t)&&(t=(s=buf)+fread(buf,1,IN_LEN,stdin)),s==t?-1:*s++;
}
template <typename _Tp> inline ios & operator >> (_Tp&x){
static char ch,sgn; ch = gc(), sgn = 0;
for(;!isdigit(ch);ch=gc()){if(ch==-1)return *this;sgn|=ch=='-';}
for(x=0;isdigit(ch);ch=gc())x=x*10+(ch^'0');
sgn&&(x=-x); return *this;
}
} io;
标签:line stdin dig 应该 return operator tchar oid char
原文地址:https://www.cnblogs.com/Thomastine/p/11754664.html