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CF1208 Red Blue Tree

时间:2019-11-01 18:44:40      阅读:74      评论:0      收藏:0      [点我收藏+]

标签:代码   codeforce   art   子节点   模板   sla   就是   Nero   思维   

题目链接

问题分析

这是蒟蒻第一道3500!不过话说luogu上两个题解的程序都是假的可还行(2019.11.1)……

为了方便叙述,下面我们约定 :

\([c]\) 的值为 \(1\) 当且仅当 \(c\) 为真,反之为 \(0\)

\(0\) 表示白色, \(1\) 表示黑色。

\(son_u\) 表示 \(u\) 的所有儿子, \(ls_u\) 表示 \(u\) 的所有轻儿子, \(hs_u\) 表示 \(u\) 的重儿子。 \(m\) 表示 \(u\) 的子节点个数。

那么实际上对于一个特定的 \(k\) ,每个点的颜色 \(C\) 都可以被这样唯一确定:
\[ C_u=\left[[C_{son_u}==1]-[C_{son_u}==0]\geqslant k\right] \]
也可以写成这样子:
\[ C_u=[m-2[C_{ls_u}==0]-2[C_{hs_u}==0]-k\geqslant 0] \]

容易发现当 \(k\) 很小时,\(C\) 一定是 \(1\)\(k\) 很大时, \(C\) 一定是 \(0\) 。进一步分析发现,对于每一个点 \(u\) ,总有一个 \(k'\) 满足 \(C_u=0(k\geqslant k')\) 并且 \(C_u=1(k<k')\) 。而如果我们能维护每一个节点 \(u\)\(k'\) (不妨记为 \(A_u\) ),就能简单地处理询问。

考虑 \(A_u\) 的性质:
\[ \begin{aligned} C_u&=[A_u>k]\A_u&=\min\{k|m-2[A_{son_u}\leqslant k]-k<0\} \end{aligned} \]
由于每次只会改变一个叶子的颜色,那么每个 \(A\) 的值最多变化2。那么可以对每一个 \(A_u\) 的儿子,可以建一个 Binary Search Tree 来解决。每一次改变暴力往前后扫 \(k\) 变了多少。时间复杂度 \(O(n^2)\)当然,如果是用脚造的数据,树高很矮的话,就可以过了

(貌似变烦而且变慢了?)

其实到这里应该已经发现是动态DP了。。。

实际上这个做法花了大量的时间转移每一个父亲,那么就可以考虑用动态DP的黑科技来转移:
\[ A_u=\min\{k|m-2[A_{ls_u}\leqslant k]-k-2[A_{hs_u}\leqslant k]<0\} \]
其中前面一部分仍然是在 Binary Search Tree 上解决,后面一部分我们需要去掉这个 \([]\) 运算。(感觉思维难点就在这里。。。)

\(T_0\) 表示当前这条链顶为白色,且链底的重儿子为白色所需最小的 \(k\)\(T_1\) 表示当前这条链顶为白色,且链底的重儿子为黑色所需要最小的 \(k\)

这样一来,重链上的转移就满足结合律了:

现在需要从链 \(B\) 转移到链 \(A\) ,其中 \(B\) 链顶的父亲是 \(A\) 链底。那么有
\[ T_0 = \min\{\max\{A_0, B_0\}, A_1\}\T_1 = \min\{\max\{A_0, B_1\}, A_1\} \]
而最后的答案就是 \([T_0>k]\) 。(考虑一下,一定有 \(T_0\leqslant T_1\) 。)

参考程序

代码很短的,很好写的,也就几个钟头就写完了。拖个模板,写的丑一点,不删调试信息也就十几k而已

#include <cstdio>
#include <algorithm>

const int INF = 1e7 + 10;
struct node {
    int Value, Priority, Size, Count;
    node *LeftChild, *RightChild;
    node() {
        Value = Priority = Size = Count = 0;
        LeftChild = RightChild = NULL;
        return;
    }
    node(int _Value) {
        Value = _Value;
        Priority = rand();
        Size = Count = 1;
        LeftChild = RightChild = NULL;
        return;
    }
    inline void Update();
};
struct noneRotateTreap {
    node *Root;
    noneRotateTreap() {
        Root = NULL;
        return;
    }
    inline std::pair<node *, node *> Split(node *Rt, int x);
    inline node *Merge(node *x, node *y);
    inline node *Find(int x);
    inline void Update(int x, int State);
    inline void Insert(int x);
    inline int Delete(int x);
    inline int Rank(int x);
    inline int Query(int x);
    inline int Precursor(int x);
    inline int Successor(int x);
    void Dfs(node *Rt);
    void Debug();
};
inline void node::Update() {
    Size = Count;
    if (LeftChild != NULL)
        Size += LeftChild->Size;
    if (RightChild != NULL)
        Size += RightChild->Size;
    return;
}

inline std::pair<node *, node *> noneRotateTreap::Split(node *Rt, int x) {
    if (Rt == NULL)
        return std::pair<node *, node *>(NULL, NULL);
    if (x < Rt->Value) {
        std::pair<node *, node *> Temp = Split(Rt->LeftChild, x);
        Rt->LeftChild = Temp.second;
        Rt->Update();
        return std::pair<node *, node *>(Temp.first, Rt);
    } else {
        std::pair<node *, node *> Temp = Split(Rt->RightChild, x);
        Rt->RightChild = Temp.first;
        Rt->Update();
        return std::pair<node *, node *>(Rt, Temp.second);
    }
}

inline node *noneRotateTreap::Merge(node *l, node *r) {
    if (l == NULL) return r;
    if (r == NULL) return l;
    if (l->Priority <= r->Priority) {
        l->RightChild = Merge(l->RightChild, r);
        l->Update();
        return l;
    } else {
        r->LeftChild = Merge(l, r->LeftChild);
        r->Update();
        return r;
    }
}

inline node *noneRotateTreap::Find(int x) {
    node *Rt = Root;
    while (Rt) {
        if (Rt->Value == x)
            return Rt;
        if (x < Rt->Value)
            Rt = Rt->LeftChild;
        else
            Rt = Rt->RightChild;
    }
    return NULL;
}

inline void noneRotateTreap::Update(int x, int State) {
    node *Rt = Root;
    while (Rt) {
        Rt->Size += State;
        if (Rt->Value == x) {
            Rt->Count += State;
            return;
        }
        if (x < Rt->Value)
            Rt = Rt->LeftChild;
        else
            Rt = Rt->RightChild;
    }
    return;
}

inline void noneRotateTreap::Insert(int x) {
    node *T = Find(x);
    if (T != NULL) {
        Update(x, 1);
        return;
    }
    std::pair<node *, node *> Temp = Split(Root, x);
    Temp.first = Merge(Temp.first, new node(x));
    Root = Merge(Temp.first, Temp.second);
    return;
}

inline int noneRotateTreap::Delete(int x) {
    node *T = Find(x);
    if (T == NULL) return 1;
    if (T->Count > 1) {
        Update(x, -1);
        return 0;
    }
    std::pair<node *, node *> Temp1 = Split(Root, x - 1);
    std::pair<node *, node *> Temp2 = Split(Temp1.second, x);
    delete Temp2.first;
    Root = Merge(Temp1.first, Temp2.second);
    return 0;
}

#define LCS (Rt->LeftChild ? Rt->LeftChild->Size : 0)

inline int noneRotateTreap::Rank(int x) {
    node *Rt = Root;
    int Ans = 0;
    while (Rt) {
        if (Rt->Value == x)
            return Ans + LCS + 1;
        if (x < Rt->Value)
            Rt = Rt->LeftChild;
        else
            Ans += LCS + Rt->Count, Rt = Rt->RightChild;
    }
    return Ans + 1;
}

inline int noneRotateTreap::Query(int x) {
    node *Rt = Root;
    while (Rt) {
        if (LCS < x && x <= LCS + Rt->Count)
            return Rt->Value;
        if (x <= LCS)
            Rt = Rt->LeftChild;
        else
            x -= LCS + Rt->Count, Rt = Rt->RightChild;
    }
    return 0;
}

#undef LCS

inline int noneRotateTreap::Precursor(int x) {
    int Ans = INF;
    node *Rt = Root;
    while (Rt) {
        if (Rt->Value < x)
            Ans = Rt->Value, Rt = Rt->RightChild;
        else
            Rt = Rt->LeftChild;
    }
    return Ans;
}

inline int noneRotateTreap::Successor(int x) {
    int Ans = -INF;
    node *Rt = Root;
    while (Rt) {
        if (Rt->Value > x)
            Ans = Rt->Value, Rt = Rt->LeftChild;
        else
            Rt = Rt->RightChild;
    }
    return Ans;
}

void noneRotateTreap::Debug() {
    Dfs(Root);
    printf("\n");
    return;
}

void noneRotateTreap::Dfs(node *T) {
    if (T == NULL) return;
    Dfs(T->LeftChild);
    for (int i = 1; i <= T->Count; ++i)
        printf("%d ", T->Value);
    Dfs(T->RightChild);
    return;
}

/*========== HEAD TEMPLATE : Binaty Search Tree -> NoneRotateTreap ==========*/

//#define DEBUG
//#define DEBUG_
//#define _DEBUG_
const int Maxn = 200010;
struct edge {
    int To, Next;
    edge() {}
    edge(int _To, int _Next) : To(_To), Next(_Next) {}
};
edge Edge[Maxn << 1];
int Start[Maxn], Used;
int Num, N, Q, Type, C[Maxn], k;
noneRotateTreap NoneRotateTreap[Maxn];
int CountSon[Maxn];
int Size[Maxn], Father[Maxn], Deep[Maxn], Son[Maxn], Top[Maxn], Dfn[Maxn], Ref[Maxn], Bottom[Maxn];
std::pair<int, int> IntervalTree[Maxn << 2];
int TreeSize;
int Record[Maxn];

inline void AddEdge(int x, int y);
inline void CutDfs1(int u, int Fa);
inline void CutDfs2(int u, int Fa);
inline std::pair<int, int> Calc(int x);
inline std::pair<int, int> Merge(std::pair<int, int> x, std::pair<int, int> y);
inline void Update(int Index, int Left, int Right);
inline void BuildIntervalTree(int Index, int Left, int Right);
inline std::pair<int, int> Query(int Index, int Left, int Right, int L, int R);
inline std::pair<int, int> Query(int x);
inline void Modify(int Pos, int &k, int Delta);
inline bool Judge(int Pos, int k, int Delta);
inline void Change(int x, int y);
inline void Modify(int Index, int Left, int Right, int Pos);

int main() {
    srand((unsigned long long)"非旋treap呀");
#ifdef DEBUG
    NoneRotateTreap[0].Insert(1);
    NoneRotateTreap[0].Insert(1);
    NoneRotateTreap[0].Insert(3);
    printf("%d %d ", NoneRotateTreap[0].Rank(2), NoneRotateTreap[0].Rank(1));
    NoneRotateTreap[0].Insert(-INF);
    printf("%d\n", NoneRotateTreap[0].Rank(1));
#endif
    scanf("%d%d", &N, &k);
    for (int i = 1; i < N; ++i) {
        int x, y;
        scanf("%d%d", &x, &y);
        AddEdge(x, y);
        AddEdge(y, x);
    }
    for (int i = 1; i <= N; ++i) scanf("%d", &C[i]);
    scanf("%d", &Q);
    CutDfs1(1, 0);
    Top[1] = 1;
    Dfn[1] = ++TreeSize;
    Ref[TreeSize] = 1;
    CutDfs2(1, 0);
    for (int i = 1; i <= N; ++i) Bottom[Top[i]] = std::max(Bottom[Top[i]], Dfn[i]);
#ifdef _DEBUG_
    printf("Father : ");
    for (int i = 1; i <= N; ++i) printf("%d ", Father[i]); printf("\n");
    printf(" Top   : ");
    for (int i = 1; i <= N; ++i) printf("%d ", Top[i]); printf("\n");
    printf(" Dfn   : ");
    for (int i = 1; i <= N; ++i) printf("%d ", Dfn[i]); printf("\n");
    printf("Bottom : ");
    for (int i = 1; i <= N; ++i) printf("%d ", Bottom[i]); printf("\n");
#endif
    BuildIntervalTree(1, 1, N);
#ifdef _DEBUG_
    printf("Check Ans :\n");
    for (int i = 1; i <= N; ++i) {
        std::pair<int, int> Ans = Query(i);
        printf("%d %d %d\n", i, Ans.first, Ans.second);
    }
#endif
    for (int i = 1; i <= N; ++i) 
        if (Top[i] == i) 
            Record[i] = Query(i).first;
    for (int i = 1; i <= Q; ++i) {
        int Opt, x, y;
        scanf("%d", &Opt);
        if (Opt == 1) {
            scanf("%d", &x);
            int Ans = Query(x).first > k ? 1 : 0;
            printf("%d\n", Ans);
        } 
        if (Opt == 2) {
            scanf("%d%d", &x, &y);
            Change(x, y);
        }
        if (Opt == 3) scanf("%d", &k);
#ifdef _DEBUG_
        printf("After Opt %d (%d-th) :\n", Opt, i);
        for (int j = 1; j <= N; ++j) {
            std::pair<int, int> Ans = Query(j);
            printf("%d %d %d\n", j, Ans.first, Ans.second);
        }
#endif
    }
    return 0;
}

inline void AddEdge(int x, int y) {
    Edge[++Used] = edge(y, Start[x]);
    Start[x] = Used;
    return;
}

inline void CutDfs1(int u, int Fa) {
    Size[u] = 1;
    Father[u] = Fa;
    Deep[u] = Deep[Fa] + 1;
    for (int t = Start[u]; t; t = Edge[t].Next) {
        int v = Edge[t].To;
        if (v == Fa) continue;
        ++CountSon[u];
        CutDfs1(v, u);
        Size[u] += Size[v];
        if (Size[v] > Size[Son[u]])
            Son[u] = v;
    }
//    if (Size[Son[u]] == 1) Son[u] = 0;
    return;
}

inline void CutDfs2(int u, int Fa) {
    if (Son[u]) {
        Top[Son[u]] = Top[u];
        Dfn[Son[u]] = ++TreeSize;
        Ref[TreeSize] = Son[u];
        CutDfs2(Son[u], u);
    }
    for (int t = Start[u]; t; t = Edge[t].Next) {
        int v = Edge[t].To;
        if (v == Fa || v == Son[u]) continue;
        Top[v] = v;
        Dfn[v] = ++TreeSize;
        Ref[TreeSize] = v;
        CutDfs2(v, u);
    }
    return;
}

inline std::pair<int, int> Merge(std::pair<int, int> x, std::pair<int, int> y) {
    std::pair<int, int> Ans;
    Ans.first = std::min(std::max(y.first, x.first), x.second);
    Ans.second = std::min(std::max(y.second, x.first), x.second);
#ifdef _DEBUG_
    printf("      Merge %d %d, %d %d, Get %d %d\n", x.first, x.second, y.first, y.second, Ans.first, Ans.second);
#endif
    return Ans;
}

inline void Update(int Index, int Left, int Right) {
    if (Left == Right) return;
    IntervalTree[Index] = Merge(IntervalTree[Index << 1], IntervalTree[Index << 1 | 1]);
    return;
}

inline void BuildIntervalTree(int Index, int Left, int Right) {
    if (Left == Right) {
//        IntervalTree[Index] = Calc(Ref[Left]);
        Modify(1, 1, N, Left); 
        //Notice : 这里需要用 Modify 同时来上传。因为下面要用到 Query(Ref[Left]) 。而 Modify 至多被调用 n 次,每次 log n ,所以不会影响复杂度。
#ifdef _DEBUG_
        printf("At Pos %d, Cal %d %d\n", Ref[Left], IntervalTree[Index].first, IntervalTree[Index].second);
#endif
        if (Top[Ref[Left]] == Ref[Left]) {
//            NoneRotateTreap[Father[Ref[Left]]].Insert(IntervalTree[Index].first);
            NoneRotateTreap[Father[Ref[Left]]].Insert(Query(Ref[Left]).first);
#ifdef _DEBUG_
            printf("*** %d\n", Ref[Left]);
            printf("!!!CAL %d %d\n", Query(Ref[Left]).first, Query(Ref[Left]).second);
            printf("Add %d To %d\n", Query(Ref[Left]).first, Father[Ref[Left]]);
            NoneRotateTreap[Father[Ref[Left]]].Debug();
#endif
        }
        return;
    }
    int Mid = (Left + Right) >> 1;
    BuildIntervalTree(Index << 1 | 1, Mid + 1, Right); //Right build first
    //Notice : 处理数据的时候要先处理深度深的链。通过线段树上先算右边再算左边就可以做到
    BuildIntervalTree(Index << 1, Left, Mid);
    Update(Index, Left, Right);
    return;
}

inline std::pair<int, int> Query(int Index, int Left, int Right, int L, int R) {
#ifdef _DEBUG_
    printf(" Query %d %d %d %d %d\n", Index, Left, Right, L, R);
#endif
    if (L <= Left && Right <= R) return IntervalTree[Index];
    int Mid = (Left + Right) >> 1;
    if (R <= Mid) return Query(Index << 1, Left, Mid, L, R);
    if (L > Mid) return Query(Index << 1 | 1, Mid + 1, Right, L, R);
    return Merge(Query(Index << 1, Left, Mid, L, R), Query(Index << 1 | 1, Mid + 1, Right, L, R));
}

inline std::pair<int, int> Calc(int x) {
    if (C[x] == 0) return std::pair<int, int>(-INF, -INF);
    if (C[x] == 1) return std::pair<int, int>(INF, INF);
//    std::pair<int, int> Temp = Query(Son[x]);
    std::pair<int, int> Ans = std::pair<int, int>(0, 0);
#ifdef DEBUG_
    printf("Son white :\n");
#endif
    Modify(x, Ans.first, 2);
#ifdef DEBUG_
    printf("Son black :\n");
#endif
    Modify(x, Ans.second, 0);
#ifdef DEBUG_
    printf("Finally get : %d %d\n", Ans.first, Ans.second);
#endif
    return Ans;
}

inline std::pair<int, int> Query(int x) {
#ifdef _DEBUG_
    printf("   Query %d -> %d %d\n", x, Dfn[x], Bottom[Top[x]]);
#endif
    return Query(1, 1, N, Dfn[x], Bottom[Top[x]]);
}

inline void Modify(int Pos, int &k, int Delta) {
    while(!Judge(Pos, k, Delta)) ++k;
    while(Judge(Pos, k - 1, Delta)) --k;
    return;
}

inline bool Judge(int Pos, int k, int Delta) {
    int m = CountSon[Pos] - k - Delta;
    int c = NoneRotateTreap[Pos].Rank(k + 1) - 1;
#ifdef DEBUG_
    printf("    Judge %d %d %d -> %d %d, %d < 0 ?\n", Pos, k, Delta, m, c, m - 2 * c);
#endif
#ifdef DEBUG
    printf("        Treap[%d], QueryRank %d, Get %d\n", Pos, k + 1, NoneRotateTreap[Pos].Rank(k + 1));
#endif
    return m - 2 * c < 0;
}

inline void Change(int x, int y) {
    C[x] = y;
    while (x) {
#ifdef _DEBUG_
        printf("Change Pos %d\n", x);
#endif
        Modify(1, 1, N, Dfn[x]);
#ifdef _DEBUG_
        printf("   Elements in Treap : ");
        NoneRotateTreap[Father[Top[x]]].Debug();
#endif
        NoneRotateTreap[Father[Top[x]]].Delete(Record[Top[x]]);
#ifdef _DEBUG_
        printf("  NoneRotateTreap %d Delete %d\n", Father[Top[x]], Record[Top[x]]);
        printf("   Elements in Treap : ");
        NoneRotateTreap[Father[Top[x]]].Debug();
#endif
        NoneRotateTreap[Father[Top[x]]].Insert(Record[Top[x]] = Query(Top[x]).first);
#ifdef _DEBUG_
        printf("  NoneRotateTreap %d Insert %d\n", Father[Top[x]], Record[Top[x]]);
        printf("   Elements in Treap : ");
        NoneRotateTreap[Father[Top[x]]].Debug();
#endif
        x = Father[Top[x]];
    }
    return;
}

inline void Modify(int Index, int Left, int Right, int Pos) {
    if (Left == Right) {
        IntervalTree[Index] = Calc(Ref[Pos]);
#ifdef _DEBUG_
        printf("   Modify %d, Get %d %d\n", Ref[Pos], IntervalTree[Index].first, IntervalTree[Index].second);
#endif
        return;
    }
    int Mid = (Left + Right) >> 1;
    if (Pos <= Mid) Modify(Index << 1, Left, Mid, Pos);
    if (Pos > Mid) Modify(Index << 1 | 1, Mid + 1, Right, Pos);
    Update(Index, Left, Right);
    return;
}

CF1208 Red Blue Tree

标签:代码   codeforce   art   子节点   模板   sla   就是   Nero   思维   

原文地址:https://www.cnblogs.com/chy-2003/p/11778439.html

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