标签:i++ lse int 生产者消费者 sum value produce 文件 rod
//生产者
func Producer(ch chan int) {
    for i := 1; i <= 10; i++ {
        ch <- i
    }
    close(ch)
}
//消费者
func Consumer(id int, ch chan int, done chan bool) {
    for {
        value, ok := <-ch
        if ok {
            fmt.Printf("id : %d consum %d value \n", id, value)
        } else {
            fmt.Printf("id : %d had closed \n", id)
            break
        }
    }
    done <- true
}
测试文件
const (
    cur int = 2
)
func main() {
    ch := make(chan int, 3)
    done := make(chan bool, 1)
    for i := 1; i <= 2; i++ {
        go Consumer(i, ch, done)
    }
    go Producer(ch)
        //注意这里,如果done channel里面没有true的化会一直阻塞直到有东西进来。
    for i := 1; i <= cur; i++ {
        <-done
    }
}标签:i++ lse int 生产者消费者 sum value produce 文件 rod
原文地址:https://www.cnblogs.com/jijiboy/p/11824514.html