标签:cout ext 计数 打印 empty off using tree ret
/* 题目: 分行按层自上向下打印二叉树。 */ /* 思路: 使用队列,将节点压入队列中,再弹出来,压入其左右子节点,循环,直到栈为空。 添加两个计数器,current记录当前行的节点数,next记录下一行的节点数。 */ #include<iostream> #include<string.h> #include<algorithm> #include<cmath> #include<stdio.h> #include<vector> #include<stack> #include<queue> using namespace std; struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } }; void PrintFromTopToBottom(TreeNode* root){ if(root == nullptr) return; deque<TreeNode*> myQueue; myQueue.push_back(root); TreeNode *temp; int current = 1; int next = 0; while(!myQueue.empty()){ temp = myQueue.front(); myQueue.pop_front(); cout<<temp->val<<" "; current--; if(temp->left != nullptr){ myQueue.push_back(temp->left); next++; } if(temp->right != nullptr){ myQueue.push_back(temp->right); next++; } if(current == 0){ cout<<endl; current = next; next = 0; } } } int main(){ TreeNode* node1 = new TreeNode(1); TreeNode* node2 = new TreeNode(2); TreeNode* node3 = new TreeNode(3); TreeNode* node4 = new TreeNode(4); TreeNode* node5 = new TreeNode(5); TreeNode* node6 = new TreeNode(6); node1->left = node2; node1->right = node3; node2->left = node4; node3->left = node5; node3->right = node6; PrintFromTopToBottom(node1); }
剑指offer-面试题32-分行从上到下打印二叉树-二叉树遍历
标签:cout ext 计数 打印 empty off using tree ret
原文地址:https://www.cnblogs.com/buaaZhhx/p/11938720.html