标签:syn mem main freopen als oid 数组 01背包 tps
题意:
题解:同Gym102222G(链接),把size数组更改一下即可。
#include <bits/stdc++.h> using namespace std; const int maxn=1e5+5; const long long inf=1e17+5; int n, m, k; int vis[maxn]; int head[maxn], degree[maxn], siz[maxn], tot; struct Edge{ int to, next, val; }edge[maxn*2]; long long dp[maxn][105]; void addedge(int u, int v, int w) { edge[++tot].to=v, edge[tot].val=w, edge[tot].next=head[u]; head[u]=tot; } void init_edge() { tot=0; memset(head, -1, sizeof(head)); memset(degree, 0, sizeof(degree)); memset(siz, 0, sizeof(siz)); memset(vis, 0, sizeof(vis)); } void init_dp() { for(int i=1; i<=n; i++) { dp[i][0]=0; for(int j=1; j<=m; j++) dp[i][j]=inf; } for(int i=1; i<=n; i++) if(vis[i]) siz[i]=1, dp[i][1]=0; } void dfs(int u, int pre) { for(int i=head[u]; i!=-1; i=edge[i].next) { int v=edge[i].to, w=edge[i].val; if(v==pre) continue; dfs(v, u); siz[u]+=siz[v]; for(int j=min(k, siz[u]); j>=1; j--) for(int kk=1; kk<=min(j, siz[v]); kk++) dp[u][j]=min(dp[u][j], dp[u][j-kk]+dp[v][kk]+1ll*w*kk*(k-kk)); } } int main() { ios::sync_with_stdio(false), cin.tie(0); //freopen("c:\\in.txt", "r", stdin); int T=1; while(T--) { init_edge(); int rt=1; cin>>n>>m>>k; for(int u,i=1; i<=m; i++) { cin>>u; vis[u]=true; } for(int u,v,w,i=1; i<n; i++) { cin>>u>>v>>w; addedge(u, v, w), addedge(v, u, w); degree[u]++, degree[v]++; if(degree[u]>1) rt=u; if(degree[v]>1) rt=v; } init_dp(); dfs(rt, 0); cout<<dp[rt][k]<<"\n"; } return 0; }
CSP认证 201909-5 城市规划(贡献+树dp+01背包)
标签:syn mem main freopen als oid 数组 01背包 tps
原文地址:https://www.cnblogs.com/Yokel062/p/11948840.html