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leetcode1272

时间:2019-12-01 11:43:29      阅读:66      评论:0      收藏:0      [点我收藏+]

标签:pen   span   end   res   col   def   rem   ret   etc   

 1 class Solution:
 2     def removeInterval(self, intervals: List[List[int]], toBeRemoved: List[int]) -> List[List[int]]:
 3         n = len(intervals)
 4         res = []
 5         for i in range(n):
 6             curent = intervals[i]
 7             if curent[1] <= toBeRemoved[0] or curent[0] >= toBeRemoved[1]:
 8                 res.append(curent)
 9             elif curent[0] >= toBeRemoved[0] and curent[1] <= toBeRemoved[1]:
10                 continue
11             elif curent[0] <= toBeRemoved[0] and curent[1] >= toBeRemoved[1]:
12                 if curent[0] != toBeRemoved[0]:
13                     res.append([curent[0],toBeRemoved[0]])
14                 if toBeRemoved[1] != curent[1]:
15                     res.append([toBeRemoved[1],curent[1]])
16             elif curent[0] <= toBeRemoved[0] and curent[1] >= toBeRemoved[0] and curent[1] <= toBeRemoved[1]:
17                 if curent[0] != toBeRemoved[0]:
18                     res.append([curent[0],toBeRemoved[0]])
19             elif curent[1] >= toBeRemoved[1] and curent[0] <= toBeRemoved[1] and curent[0] >= toBeRemoved[0]:
20                 if toBeRemoved[1] != curent[1]:
21                     res.append([toBeRemoved[1],curent[1]])
22         return res

分6种情况讨论(第一个if语句是两种情况)

leetcode1272

标签:pen   span   end   res   col   def   rem   ret   etc   

原文地址:https://www.cnblogs.com/asenyang/p/11965148.html

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