标签:accept int tin share tor style cep possible put
Given an array of integers A, a move consists of choosing any A[i]
, and incrementing it by 1
.
Return the least number of moves to make every value in A
unique.
Example 1:
Input: [1,2,2]
Output: 1
Explanation: After 1 move, the array could be [1, 2, 3].
Example 2:
Input: [3,2,1,2,1,7]
Output: 6
Explanation: After 6 moves, the array could be [3, 4, 1, 2, 5, 7].
It can be shown with 5 or less moves that it is impossible for the array to have all unique values.
Note:
0 <= A.length <= 40000
0 <= A[i] < 40000
class Solution { public: int minIncrementForUnique(vector<int>& A) { sort(A.begin(),A.end()); int res=0,need=0; for(int i=0;i<A.size();++i) { res+=max(need-A[i],0); need=max(need,A[i])+1; } return res; } };
945. Minimum Increment to Make Array Unique
标签:accept int tin share tor style cep possible put
原文地址:https://www.cnblogs.com/lychnis/p/11992674.html