CodeForces - 841B-Godsend-思维

标签：one   math   god   nbsp   map   include   +=   while   input   

Leha somehow found an array consisting of n integers. Looking at it, he came up with a task. Two players play the game on the array. Players move one by one. The first player can choose for his move a subsegment of non-zero length with an odd sum of numbers and remove it from the array, after that the remaining parts are glued together into one array and the game continues. The second player can choose a subsegment of non-zero length with an even sum and remove it. Loses the one who can not make a move. Who will win if both play optimally?

Input

First line of input data contains single integer n (1 ≤ n ≤ 10⁶) — length of the array.

Next line contains n integers a₁, a₂, ..., a_n (0 ≤ a_i ≤ 10⁹).

Output

Output answer in single line. "First", if first player wins, and "Second" otherwise (without quotes).

Examples

4
1 3 2 3

First

2
2 2

Second

Note

In first sample first player remove whole array in one move and win.

In second sample first player can‘t make a move and lose.

 1 #include<stdio.h>
 2 #include<map>
 3 #include<iostream>
 4 #include<string.h>
 5 #include<algorithm>
 6 #include<stack>
 7 #include<cmath>
 8 #include<vector>
 9 using namespace std;
10 typedef long long ll;
11 
12 
13 int a[1000020];
14 
15 int main()
16 {
17     int n;
18     while(cin>>n)
19     {
20         ll sum=0;
21         int flag=0;
22         for(int i=0;i<n;i++)
23         {
24             cin>>a[i];
25             if(a[i]%2==1)
26                 flag=1;
27             sum+=a[i];
28         }
29         if(sum%2==1)
30             cout<<"First"<<endl;
31         else
32         {
33             if(flag==0)
34                 cout<<"Second"<<endl;
35             else
36                 cout<<"First"<<endl;
37         }
38 
39     }
40     return 0;
41 }

CodeForces - 841B-Godsend-思维

标签：one   math   god   nbsp   map   include   +=   while   input   

原文地址：https://www.cnblogs.com/OFSHK/p/11992855.html