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汇编模拟钢琴

时间:2014-10-30 20:54:15      阅读:234      评论:0      收藏:0      [点我收藏+]

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;比较low的钢琴
ASSUME CS:CODE,DS:DATA,SS:STACK
DATA  SEGMENT    
    ;设置键盘区位 
    ;中音区 A: 7 S: 8 D: 9 F:10 J:11 K:12 L:13
    ;高音区 Q:14 W:15 E:16 R:17 U:18 I:19 O:20
    ;低音区 Z: 0 X: 1 C: 2 V: 3 B: 4 N: 5 M: 6 
    ;填补区 T:17 Y:18 G:10 H:11 P:20 
    ;       ‘[‘:20 ‘]‘:20 ‘;‘:14 ‘"‘:14 ‘<‘:
    ;       ‘<‘:5 ‘>‘:5 ‘\‘:6 
    ;       ‘^‘:0 ‘-‘:0 ‘`‘:0 
    ;由于acsii码‘A‘的号码较小,为了大小写一致,直接减去‘A‘则得到序号为
    NORMALF DD 119000
    TIME DW 0
    IND DB    7,4,2,9,16,10,10,11,19,11,12,13,6,5,20,20,14,17,8,17,18,3,15,1,18,0,20,6,20,0,0,0,7,4,2,9,16,10,10,11,19,11,12,13,6,5,20,20,14,17,8,17,18,3,15,1,18,0
    FRE DW    131,147,165,175,196,220,247,262,294,330,349,392,440,494, 524,587,659,698,784,880,988
    STR1 DB "Welcome!!$"
    STR2 DB "The keyboard is distributed like that:$"
    STR3 DB "0 exit$"
    STR4 DB "High   Q W E R U I O$"
    STR5 DB "Medium A S D F J K L$"
    STR6 DB "Low    Z X C V B N M$"
    LENSTR DW 10,39,7,21,21  
DATA ENDS

STACK SEGMENT
    BUFF DB 80H DUP(0) 
STACK ENDS

CODE SEGMENT
    INIT PROC                         ;直接把所有频率除以基准频率
       MOV CX,21
       MOV DI,0
       LOOP1:
       MOV DX,NORMALF[2]
       MOV AX,NORMALF 
       DIV FRE[DI]
       MOV FRE[DI],AX
       ADD DI,2
       LOOP LOOP1   
       
       MOV CX,5                        ;输出提示语
       LEA DI,STR1
       MOV AX,0900H
       MOV DX,DI
       MOV SI,0
       INT 21H      
       CALL NEWLINE
       LOOP3:
       ADD DI,LENSTR[SI]
       ADD SI,2
       MOV DX,DI  
       MOV AX,0900H
       INT 21H     
       CALL NEWLINE
       LOOP LOOP3
       
       RET
    INIT ENDP
    
    RING PROC                         ;此时调用的字符存储在栈中
       POP SI
       POP DI
       SUB DI,‘A‘
       MOV AL,IND[DI]
       MOV DI,AX      
       ADD DI,DI 
       MOV AX,0
       
       MOV AL,0B6H
       OUT 43H,AL
       MOV AL,BYTE PTR FRE[DI]
       OUT 42H,AL
       MOV AL,BYTE PTR FRE[DI+1]
       OUT 42H,AL  
       IN  AL,61H
       OR  AL,3
       OUT 61H,AL
       
       MOV AL,0 
       INT 1AH
       MOV TIME,DX
       BACK1:
       MOV AL,0
       INT 1AH
       SUB DX,TIME
       CMP DX,5H
       JB BACK1  
       MOV AX,0
       OUT 61H,AL
       PUSH SI
       RET
    RING ENDP    
    
    NEWLINE PROC
      MOV AH,02H
      MOV DL,0DH
      INT 21H     
      MOV AH,02H
      MOV DL,0AH
      INT 21H
      RET
    NEWLINE ENDP
        
    BEGIN:
    MOV AX,DATA
    MOV DS,AX   
    MOV AX,STACK
    MOV SS,AX
    CALL INIT
    
    
    LOOP2: 
    MOV AH,01H
    INT 21H
    CMP AL,‘A‘
    JB EXIT
    CMP AL,‘z‘
    JA EXIT     
    MOV AH,0
    PUSH AX
    CALL RING
    JMP LOOP2
 
    EXIT:
    MOV AX,4C00H
    INT 21H
CODE ENDS
END BEGIN
            

  

汇编模拟钢琴

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原文地址:http://www.cnblogs.com/xuesu/p/4063566.html

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