标签:trunc roman dig rom dex repeat 区间 pow 数字
从最高位到最低位
const roman = {
4: ['M', 'MM', 'MMM'],
3: [
'C', 'CC', 'CCC', 'CD', 'D', 'DC', 'DCC', 'DCCC', 'CM'
],
2: [
'X', 'XX', 'XXX', 'XL', 'L', 'LX', 'LXX', 'LXXX', 'XC'
],
1: [
'I', 'II', 'III', 'IV', 'V', 'VI', 'VII', 'VIII', 'IX'
]
}
var intToRoman = function (num) {
let ret = ''
let digit = ~~Math.log10(num, 10) + 1; //至少有一位
let divisor = Math.pow(10, digit - 1);
while (num > 0) {
var index = Math.floor(num / divisor); //最高位
ret += roman[digit][index - 1] || "";//处理101的情况
num -= index * divisor;//去掉最高位
digit -= 1; //减少层级
divisor /= 10//减少除数
}
return ret;
};
从最低位到最高位
var symbols = [
[
"I",
"II",
"III",
"IV",
"V",
"VI",
"VII",
"VIII",
"IX"
],
[
"X",//10
"XX",//20
"XXX",//30
"XL",//40
"L",//50
"LX",//60
"LXX",//70
"LXXX",//80
"XC",//90
],
[
"C",//100
"CC",//200
"CCC",//300
"CD",//400
"D",//500
"DC",//600
"DCC",//700
"DCCC",//800
"CM",//900
],
[
"M",//1000
"MM",//2000
"MMM"//3000
]
]
var intToRoman = function (num) {
var roman = "", digit = 0
while (num >= 1) {
var index = num % 10
var num = Math.trunc(num / 10)
var romans = symbols[digit]
var cur = romans[index - 1] || ""
roman = cur + roman
digit++
}
return roman
};
另一种从高到底
var intToRoman = function(num) {
const roman = {
'M':1000,
'CM':900,
'D':500,
'CD':400,
'C':100,
'XC':90,
'L':50,
'XL':40,
'X':10,
'IX':9,
'V':5,
'IV':4,
'I': 1,
}
let result = ''
for(let key in roman){
//先判定数字在哪个区间中
if(num >= roman[key]){
let divisor = Math.trunc(num / roman[key])
result += key.repeat(divisor)
num -= roman[key] * divisor
}
}
return result
};
标签:trunc roman dig rom dex repeat 区间 pow 数字
原文地址:https://www.cnblogs.com/rubylouvre/p/12040297.html