[LC] 674. Longest Continuous Increasing Subsequence

标签：lcis   pre   max   and   else   seq   null   bar   The   

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it‘s not a continuous one where 5 and 7 are separated by 4. 

Example 2:

Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 

Note: Length of the array will not exceed 10,000.

class Solution {
    public int findLengthOfLCIS(int[] nums) {
        if (nums == null || nums.length == 0) {
            return 0;
        }
        int cur = 1, res = 1;
        for (int i = 1; i < nums.length; i++) {
            if (nums[i] > nums[i - 1]) {
                cur += 1;
                res = Math.max(res, cur);
            } else {
                cur = 1;
            }        
        }
        return res;
    }
}

[LC] 674. Longest Continuous Increasing Subsequence

标签：lcis   pre   max   and   else   seq   null   bar   The   

原文地址：https://www.cnblogs.com/xuanlu/p/12041783.html