标签：only value point inpu div any imu public tar
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
Example:
Input: [ [1,3,1], [1,5,1], [4,2,1] ] Output: 7 Explanation: Because the path 1→3→1→1→1 minimizes the sum.
class Solution { public int minPathSum(int[][] grid) { int row = grid.length; int col = grid[0].length; int[][] paths = new int[row][col]; paths[0][0] = grid[0][0]; // start from 1 should include the current grid value and prev value for (int i = 1; i < row; i++) { paths[i][0] = grid[i][0] + paths[i - 1][0]; } for (int i = 1; i < col; i++) { paths[0][i] = grid[0][i] + paths[0][i - 1]; } for (int i = 1; i < row; i++) { for (int j = 1; j < col; j++) { paths[i][j] = Math.min(paths[i - 1][j], paths[i][j - 1]) + grid[i][j]; } } return paths[row - 1][col - 1]; } }
标签：only value point inpu div any imu public tar
原文地址：https://www.cnblogs.com/xuanlu/p/12047225.html
