标签:order turn 后序 oid break 一个 子序列 中序遍历 string
如何通过后序遍历序列和中序遍历序列来确定一棵二叉树??
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <string.h> 4 5 struct node 6 { 7 char data; 8 struct node *lt, *rt; 9 }; 10 11 // 用先序序列和中序序列建立二叉树 12 struct node *create_by_pre_and_mid(int n, char *pre, char *mid) 13 { 14 struct node *root; 15 int i; 16 17 if(n==0) 18 return NULL; 19 20 root=(struct node *)malloc(sizeof(struct node)); 21 root->data=pre[0]; 22 23 for(i=0;i<n;i++) // 寻找左右子树的元素 24 if(pre[0]==mid[i]) 25 break; 26 27 root->lt = create_by_pre_and_mid(i, pre+1, mid); // 建立左子树 28 root->rt = create_by_pre_and_mid(n-i-1, pre+i+1, mid+i+1); // 建立右子树 29 30 return root; 31 } 32 33 // 用后序序列和中序序列建立二叉树 34 struct node *create_by_post_and_mid(int n, char *post, char *mid) 35 { 36 struct node *root; 37 int i; 38 39 if(n==0) 40 return NULL; 41 42 root=(struct node *)malloc(sizeof(struct node)); 43 root->data=post[n-1]; 44 45 for(i=0;i<n;i++) // 寻找左右子树的元素 46 if(post[n-1]==mid[i]) 47 break; 48 49 root->lt = create_by_post_and_mid(i, post, mid); // 建立左子树 50 root->rt = create_by_post_and_mid(n-i-1, post+i, mid+i+1); // 建立右子树 51 52 return root; 53 } 54 55 // 后序遍历 56 void postorder(struct node *root) 57 { 58 if(root) 59 { 60 postorder(root->lt); 61 postorder(root->rt); 62 printf("%c", root->data); 63 } 64 } 65 66 // 前序遍历 67 void preorder(struct node *root) 68 { 69 if(root) 70 { 71 printf("%c", root->data); 72 preorder(root->lt); 73 preorder(root->rt); 74 } 75 } 76 77 // 中序遍历 78 void midorder(struct node *root) 79 { 80 if(root) 81 { 82 midorder(root->lt); 83 printf("%c", root->data); 84 midorder(root->rt); 85 } 86 } 87 88 89 int main( void ) 90 { 91 struct node *root=NULL; 92 int len; 93 char *post = "DFEBGIHCA"; 94 char *pre = "ABDEFCGHI"; 95 char *mid = "DBFEAGCHI"; 96 97 len=strlen(post); 98 99 //root=create_by_pre_and_mid(len, pre, mid); 100 root = create_by_post_and_mid(len, post, mid); 101 102 printf("\r\npreorder:\r\n"); 103 preorder(root); 104 105 printf("\r\nmidorder:\r\n"); 106 midorder(root); 107 108 printf("\r\npostorder:\r\n"); 109 postorder(root); 110 111 printf("\r\n"); 112 113 114 system("pause"); 115 return 0; 116 }
标签:order turn 后序 oid break 一个 子序列 中序遍历 string
原文地址:https://www.cnblogs.com/utank/p/12048345.html