标签:blog io ar for sp on 2014 log amp
最多只需要封锁4个区域即可,DFS封锁的区域,BFS是否可通过
#include "stdio.h" #include "string.h" #include "queue" using namespace std; int dir[4][2]={{1,0},{-1,0},{0,1},{0,-1}}; int s_x,s_y,n,m,t; char str[11][11]; struct node { int x,y,step,key; }; int bfs() { queue<node>q; node cur,next; int i; int hash[11][11][2]; cur.x=s_x; cur.y=s_y; cur.step=0; cur.key=0; q.push(cur); memset(hash,0,sizeof(hash)); hash[s_x][s_y][0]=1; while (!q.empty()) { cur=q.front(); q.pop(); if (cur.step>=t) return -1; for (i=0;i<4;i++) { next.x=cur.x+dir[i][0]; next.y=cur.y+dir[i][1]; if (next.x<0 || next.y<0 || next.x>=n || next.y>=m) continue; if (str[next.x][next.y]=='#') continue; next.step=cur.step+1; next.key=cur.key; if (str[next.x][next.y]=='J') next.key=1; if (hash[next.x][next.y][next.key]==1) continue; hash[next.x][next.y][next.key]=1; q.push(next); if (str[next.x][next.y]=='E' && next.key==1) return 1; } } return -1; } int dfs(int k) { int i,j; char ch; if (k==0) return bfs(); for (i=0;i<n;i++) for (j=0;j<m;j++) if (str[i][j]=='J' || str[i][j]=='.') { ch=str[i][j]; str[i][j]='#'; if (dfs(k-1)==-1) return -1; str[i][j]=ch; } return 1; } int main() { int Case,i,j; scanf("%d",&Case); while (Case--) { scanf("%d%d%d",&n,&m,&t); for (i=0; i<n; i++) { scanf("%s",str[i]); for (j=0; j<m; j++) if(str[i][j]=='S') { s_x=i; s_y=j; break; } } if (bfs()==-1) { printf("0\n"); continue; } if (dfs(1)==-1) printf("1\n"); else if (dfs(2)==-1) printf("2\n"); else if (dfs(3)==-1) printf("3\n"); else printf("4\n"); } return 0; }
标签:blog io ar for sp on 2014 log amp
原文地址:http://blog.csdn.net/u011932355/article/details/40649961