题目1002：Grading

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题目描述：

    Grading hundreds of thousands of Graduate Entrance Exams is a hard work. It is even harder to design a process to make the results as fair as possible. One way is to assign each exam problem to 3 independent experts. If they do not agree to each other, a judge is invited to make the final decision. Now you are asked to write a program to help this process.
    For each problem, there is a full-mark P and a tolerance T(<P) given. The grading rules are:
    • A problem will first be assigned to 2 experts, to obtain G1 and G2. If the difference is within the tolerance, that is, if |G1 - G2| ≤ T, this problem‘s grade will be the average of G1 and G2.
    • If the difference exceeds T, the 3rd expert will give G3.
    • If G3 is within the tolerance with either G1 or G2, but NOT both, then this problem‘s grade will be the average of G3 and the closest grade.
    • If G3 is within the tolerance with both G1 and G2, then this problem‘s grade will be the maximum of the three grades.
    • If G3 is within the tolerance with neither G1 nor G2, a judge will give the final grade GJ.

输入：

    Each input file may contain more than one test case.
    Each case occupies a line containing six positive integers: P, T, G1, G2, G3, and GJ, as described in the problem. It is guaranteed that all the grades are valid, that is, in the interval [0, P].

输出：

    For each test case you should output the final grade of the problem in a line. The answer must be accurate to 1 decimal place.

样例输入：

20 2 15 13 10 18

样例输出：

14.0

Java Code

import java.util.Scanner;

public class Main{   
    public static void main(String[] args) {
        Scanner  in = new  Scanner(System.in);
        while(in.hasNextInt()){
            int P = in.nextInt();
            int T = in.nextInt();
            int G1 = in.nextInt();
            int G2 = in.nextInt();
            int G3 = in.nextInt();
            int GJ = in.nextInt();
            
            float grade = 0 ;
            
            int a = Math.abs(G1 - G2);
            int b = Math.abs(G1 - G3);
            int c = Math.abs(G2 - G3);
            
            if(a <= T)
                grade = (float)(G1 + G2)/2;
            else{
                if((b <= T) && (c <= T)){
                    int temp = G1 > G2 ? G1 : G2;    
                    grade = temp > G3 ? temp :G3;
                }
                
                if((b > T) && (c > T))
                    grade = GJ;
                if(b <= T)
                    grade = (float)(G1 + G3)/2;
                if(c <= T)
                    grade = (float)(G2 + G3)/2;                    
            }
            System.out.println(grade);
            
        }
    }

}

 

题目1002：Grading

标签：des   style   blog   io   color   os   ar   java   for   

原文地址：http://www.cnblogs.com/Mokaffe/p/4065644.html