L1-064 估值一亿的AI核心代码 (20分) 团体程序设计天梯赛-练习集

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int n,len;
char s[1050],t[1050];
void print(char *str,int *c) {
    if(!isalnum(str[*c])) {
        printf("%c",str[*c]);
        *c += 1;
        if(str[*c] == ‘ ‘) *c += 1;
        return;
    }
    if(*c && str[*c - 1] == ‘ ‘) printf(" ");
    char temp1[1050],temp2[1050] = "";
    sscanf(str + *c,"%s",temp1);
    if(strcmp(temp1,"I") == 0 || strcmp(temp1,"me") == 0) {
        printf("you");
        *c += strlen(temp1) + 1;
    }
    else if(strcmp(temp1,"can") == 0 || strcmp(temp1,"could") == 0) {
        *c += strlen(temp1) + 1;
        if(*c < len) {
            sscanf(str + *c,"%s",temp2);
        }
        if(strcmp(temp2,"you") == 0) {
            printf("I %s",temp1);
            *c += strlen(temp2) + 1;
        }
        else printf("%s",temp1);
    }
    else {
        printf("%s",temp1);
        *c += strlen(temp1) + 1;
    }
}
int main() {
    scanf("%d",&n);
    getchar();
    for(int i = 0;i < n;i ++) {
        int k = 0,c = 0;
        while((s[k] = getchar()) != ‘\n‘) {
            if(s[k] == ‘ ‘) {
                if(c && t[c - 1] != ‘ ‘) t[c ++] = ‘ ‘;
            }
            else if(!isalnum(s[k])) {
                if(c && t[c - 1] != ‘ ‘) t[c ++] = ‘ ‘;
                if(s[k] == ‘?‘) t[c ++] = ‘!‘;
                else t[c ++] = s[k];
            }
            else {
                if(s[k] != ‘I‘) t[c ++] = tolower(s[k]);
                else t[c ++] = s[k];
            }
            k ++;
        }
        while(t[c - 1] == ‘ ‘) c --;
        s[k] = 0;
        t[c] = 0;
        printf("%s\nAI: ",s);
        len = c;
        c = 0;
        while(c < len) {
            print(t,&c);
        }
        printf("\n");
    }
    return 0;
}