标签:style blog http io color os ar java for
Anagrams
Given an array of strings, return all groups of strings that are anagrams.
Note: All inputs will be in lower-case.
思路:
建Hashtable,用排序过的string作为key,它的anagram作为ArrayList
这道题之前用暴力写的O(N^2)的TLE了,改用Hashtable来写
题目的意思是给一个String数组,找出其中由相同字母组成的单词。
例如:
S = ["abc", "bca", "bac", "bbb", "bbca", "abcb"]
答案为:
["abc", "bca", "bac", "bbca", "abcb"]
只有"bbb"没有相同字母组成的单词。
ref: http://blog.csdn.net/fightforyourdream/article/details/14217985
1 public class Solution { 2 public List<String> anagrams(String[] strs) { 3 List<String> ret = new ArrayList<String>(); 4 5 if (strs == null) { 6 return ret; 7 } 8 9 HashMap<String, List<String>> map = new HashMap<String, List<String>>(); 10 11 int len = strs.length; 12 for (int i = 0; i < len; i++) { 13 String s = strs[i]; 14 15 // Sort the string. 16 char[] chars = s.toCharArray(); 17 Arrays.sort(chars); 18 String strSort = new String(chars); 19 20 // Create a ArrayList for the sorted string. 21 if (!map.containsKey(strSort)) { 22 map.put(strSort, new ArrayList<String>()); 23 } 24 25 // Add a new string to the list of the hashmap. 26 map.get(strSort).add(s); 27 } 28 29 // go through the map and add all the strings into the result. 30 for (Map.Entry<String, List<String>> entry: map.entrySet()) { 31 List<String> list = entry.getValue(); 32 33 // skip the entries which only have one string. 34 if (list.size() == 1) { 35 continue; 36 } 37 38 // add the strings into the list. 39 ret.addAll(list); 40 } 41 42 return ret; 43 } 44 }
https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/hash/Anagrams.java
标签:style blog http io color os ar java for
原文地址:http://www.cnblogs.com/yuzhangcmu/p/4067507.html