leetcode-32

public class Solution {
    public boolean isValid(String s) {
        Stack<Character> stack = new Stack<Character>();
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == ‘(‘) {
                stack.push(‘(‘);
            } else if (!stack.empty() && stack.peek() == ‘(‘) {
                stack.pop();
            } else {
                return false;
            }
        }
        return stack.empty();
    }
    public int longestValidParentheses(String s) {
        int maxlen = 0;
        for (int i = 0; i < s.length(); i++) {
            for (int j = i + 2; j <= s.length(); j+=2) {
                if (isValid(s.substring(i, j))) {
                    maxlen = Math.max(maxlen, j - i);
                }
            }
        }
        return maxlen;
    }
}

    public static int longestValidParentheses(String s) {
        int maxans = 0;
        Stack<Integer> stack = new Stack<>();
        stack.push(-1);　　　　　　　　　　　　　　// 这里相当于设置一个比较位置
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == ‘(‘) {
                stack.push(i);
            } else {
                stack.pop();
                if (stack.empty()) {　　　　　　// 当为空的时候，说明已经出现了一种（）（））的情况，说明我们如果要继续下去只能从最后这个）开始作为一个新的起始点来比较
                    stack.push(i);
                } else {
                    maxans = Math.max(maxans, i - stack.peek());
                }
            }
        }
        return maxans;
    }

public class Solution {
    public int longestValidParentheses(String s) {
        int left = 0, right = 0, maxlength = 0;
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == ‘(‘) {
                left++;
            } else {
                right++;
            }
            if (left == right) {
                maxlength = Math.max(maxlength, 2 * right);
            } else if (right >= left) {
                left = right = 0;
            }
        }
        left = right = 0;
        for (int i = s.length() - 1; i >= 0; i--) {
            if (s.charAt(i) == ‘(‘) {
                left++;
            } else {
                right++;
            }
            if (left == right) {
                maxlength = Math.max(maxlength, 2 * left);
            } else if (left >= right) {
                left = right = 0;
            }
        }
        return maxlength;
    }
}