标签:pareto ati ecif compare sed space sep int a+b
Given three integers A, B and C in [−], you are supposed to tell whether A+B>C.
The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
For each test case, output in one line Case #X: true
if A+B>C, or Case #X: false
otherwise, where X is the case number (starting from 1).
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Case #1: false
Case #2: true
Case #3: false
大数用Java比较方便
import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int N=sc.nextInt(); BigInteger A,B,C; for(int i=1;i<=N;i++){ A=sc.nextBigInteger(); B=sc.nextBigInteger(); C=sc.nextBigInteger(); if(A.add(B).compareTo(C)>0){ System.out.printf("Case #%d: true\n",i); }else{ System.out.printf("Case #%d: false\n",i); } } } }
PAT Advanced 1065 A+B and C (64bit) (20分)
标签:pareto ati ecif compare sed space sep int a+b
原文地址:https://www.cnblogs.com/littlepage/p/12216124.html