标签:ber algo with 使用 find 一个 sort jks https
1 from heapq import heappush, heappop 2 class Solution: 3 def findTheCity(self, n: int, edges: ‘List[List[int]]‘, distanceThreshold: int) -> int: 4 dis = [[float(‘inf‘)]*n for _ in range(n)] 5 nei = collections.defaultdict(list) 6 for i,j,x in edges: 7 dis[i][j] = dis[j][i] = x 8 nei[i].append(j) 9 nei[j].append(i) 10 for i in range(n): 11 dis[i][i] = 0 12 13 # Dijkstra 14 visited = set() 15 for i in range(n): 16 pool = [(0,i)] # pool[j] = x: d(i,j) = x 17 while pool: 18 x,j = heappop(pool) # x = d(i,j) 19 if (i,j) not in visited and x <= distanceThreshold: # early stop, if distance exceeds threshold 20 visited.add((i,j)) 21 for k in nei[j]: 22 dis[i][k] = min(dis[i][k], x+dis[j][k]) # dis(i,k) = min(dis(i,k), dis(i,j)+dis(j,k)) 23 heappush(pool, (dis[i][k], k)) 24 cities = [[i,0] for i in range(n)] 25 for i in range(n): 26 for d in dis[i]: 27 if d <= distanceThreshold: 28 cities[i][1] += 1 29 result = sorted(cities,key=lambda x:[x[1],-x[0]])[0][0] 30 return result
算法思路:图,单源最短路径,Dijkstra算法。
计算每一个点到其他可达点的最小路径,再与阈值进行比较。统计每一个城市为起点,满足阈值范围内的可到达的其他城市的数量,再使用双条件排序,得到最终结果。
24-29行,是我自己的代码,比原帖中的写的要容易理解一些。
标签:ber algo with 使用 find 一个 sort jks https
原文地址:https://www.cnblogs.com/asenyang/p/12234539.html