标签:check main size uri sys com ace print int
利用前缀和维护钻石的价值,然后枚举左端点,二分查找右端点。
#include<bits/stdc++.h>
using namespace std;
int n,m,pre_sum[100005];
vector<int> ans;
void check(int i,int &j,int &check);
int main()
{
int i,j,mmin,result;
scanf("%d%d",&n,&m);
for(i=1;i<=n;i++)
{
scanf("%d",&pre_sum[i]);
pre_sum[i]+=pre_sum[i-1];
}
for(i=1,mmin=pre_sum[n];i<=n;i++)
{
check(i,j,result);
if(result>mmin) continue;
if(result>=m)
{
if(result<mmin)
{
ans.clear();
mmin=result;
}
ans.push_back(i);
ans.push_back(j);
}
}
for(i=0;i<ans.size()-1;i+=2)
printf("%d-%d\n",ans[i],ans[i+1]);
system("pause");
return 0;
}
void check(int i,int &j,int &result)
{
int left=i,right=n,mid;
while(left<=right)
{
mid=(left+right)/2;
if(pre_sum[mid]-pre_sum[i-1]>=m) j=mid,right=mid-1;
else left=mid+1;
}
result=pre_sum[j]-pre_sum[i-1];
}
PAT (Advanced Level) 1044 Shopping in Mars
标签:check main size uri sys com ace print int
原文地址:https://www.cnblogs.com/VividBinGo/p/12238003.html