标签:time else string insert 越界 alt mic http include
#include<iostream> #include<map> #include<set> #include<vector> //研究一下stringToInt using namespace std; map<string,int>stringToInt; map<string,int>time1; set<string>s; map<int,string>IntTostring; const int MAXV=1010; bool G[MAXV][MAXV]={false}; int weight[MAXV][MAXV],we[MAXV]={0},count=0,tot=0,aut=0,head,max1,tot1=0,maxv; bool visited[MAXV]; vector<int>v1; vector<int>v2; int reverse(string s){ if(stringToInt[s]==0){ stringToInt[s]=++aut; IntTostring[aut]=s; maxv=aut; return aut; }else return stringToInt[s]; } int DFS(int v){ count++; visited[v]=true; for(int i=1;i<MAXV;i++){ if(weight[v][i]!=0&&!G[v][i]){ tot+=weight[v][i]; G[v][i]=true; if(we[i]>max1){ max1=we[i]; head=i; } if(!visited[i]) DFS(i); } } return head; } int main(){ int n,sx,w; string name1,name2; cin>>n>>sx; for(int i=0;i<n;i++){ cin>>name1>>name2>>w; int n1=reverse(name1); int n2=reverse(name2);//转成数字 we[n1]+=w; we[n2]+=w; weight[n1][n2]=w; } for(int i=1;i<MAXV;i++){ if(!visited[i]){ count=0; tot=0; tot1++; max1=we[i]; head=i; int head=DFS(i); if(tot>sx&&count>2){ // v1.push_back(head); // v2.push_back(count); time1[IntTostring[head]]=count; s.insert(IntTostring[head]); } } } cout<<s.size()<<endl; for(auto it=s.begin();it!=s.end();it++){ cout<<*it<<" "<<time1[*it]<<endl; } return 0; }
这个代码的第三个测试点因为段错误而错误,但是始终找不到错误点,猜测和数组越界无关而和递归溢出有关
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在实现字符串对数的映射时可以使用:
int reverse(string s){ if(stringToInt[s]==0){ stringToInt[s]=++aut; IntTostring[aut]=s; maxv=aut; cout<<" ---------------"<<s<<" 对应 "<<aut<<endl; return aut; }else return stringToInt[s]; }
另外我发现在pat上能跑出来的代码。上传到牛客网上最多只能对一半 让人心慌
标签:time else string insert 越界 alt mic http include
原文地址:https://www.cnblogs.com/tao7/p/12243209.html