Wormhole

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <string>
 4 #include <cstring>
 5 #include <string>
 6 #include <cmath>
 7 #include <cstdlib>
 8 #include <algorithm>
 9 #include <bits/stdc++.h>
10 using namespace std;
11 typedef long long ll;
12 const int maxn = 65;
13 const int inf=0x3f3f3f3f;
14 const ll mod=1e9+7;
15 
16 map<string,int>mp;
17 int n,w,q;
18 struct node{
19     ll xi,yi,zi;
20 //    string s;
21 }a[maxn];
22 double f[maxn][maxn];
23 double h[maxn];
24 string s1[maxn], s2[maxn];
25 
26 void floyd(){
27     for(int k=0;k<n;k++){
28         for(int i=0;i<n;i++){
29             for(int j=0;j<n;j++){
30                 if( f[i][j]>f[i][k]+f[k][j]){
31                     f[i][j]=f[i][k]+f[k][j];
32                 }
33             }
34         }
35     }
36 }
37 
38 void init(){
39     for(int i=0;i<n;i++){
40         for(int j=i+1;j<n;j++){
41             ll x=abs(a[i].xi-a[j].xi);
42             ll y=abs(a[i].yi-a[j].yi);
43             ll z=abs(a[i].zi-a[j].zi);
44             f[i][j]=(double)sqrt(1.0*x*x+1.0*y*y+1.0*z*z);
45             f[j][i]=f[i][j];
46         }
47     }
48 }
49 
50 int main()
51 {
52     int t,cas=0;
53     scanf("%d",&t);
54     while( t-- ){
55         string ss,sss;
56         memset(a,0,sizeof(a));
57         scanf("%d",&n);
58         for(int i=0;i<n;i++){
59             ll x,y,z;
60             cin>>ss>>x>>y>>z;
61             mp[ss]=i;
62 //            a.s = ss;
63             a[i].xi = x;
64             a[i].yi = y;
65             a[i].zi = z;
66         }
67         init();
68         scanf("%d",&w);
69         for(int i=0;i<w;i++){
70             cin>>ss>>sss;
71             int u=mp[ss];
72             int v=mp[sss];
73             f[u][v]=0.0;
74         }
75         floyd();
76         scanf("%d",&q);
77         for(int i=0;i<q;i++){
78             cin>>s1[i]>>s2[i];
79             int u=mp[s1[i]];
80             int v=mp[s2[i]];
81             h[i]=f[u][v];
82         }
83         printf("Case %d:\n", ++cas);
84         for(int i=0;i<q;i++){
85 //            int u=mp[s1[i]];
86 //            int v=mp[s2[i]];
87             cout<<"The distance from "<<s1[i]<<" to "<<s2[i]<<" is ";
88             printf("%.0f",h[i]);
89             cout<<" parsecs."<<endl;
90         }
91     }
92     return 0;
93 }