hdu 2011 多项式求和

#include<iostream>
using namespace std;
int main(){
    int i, n;
    int t = 1;
    int cnt;
    double sum, num;
    while (cin >> n)
    {
        while (n--)
        {
            cin >> cnt;
            sum = 0;
            t = 1;
            for (i = 1; i <= cnt; i++)
            {
                num = (double)t / (double)i;
                sum = sum + num;
                t = t*-1;
            }
            printf("%0.2lf\n", sum);
        }

    }

    system("pause");
    return 0;
}