【leetcode】1342. Number of Steps to Reduce a Number to Zero

标签：def   other   constrain   out   style   代码   output   sub   step   

题目如下：

Given a non-negative integer num, return the number of steps to reduce it to zero. If the current number is even, you have to divide it by 2, otherwise, you have to subtract 1 from it.

Example 1:

Input: num = 14
Output: 6
Explanation: 
Step 1) 14 is even; divide by 2 and obtain 7. 
Step 2) 7 is odd; subtract 1 and obtain 6.
Step 3) 6 is even; divide by 2 and obtain 3. 
Step 4) 3 is odd; subtract 1 and obtain 2. 
Step 5) 2 is even; divide by 2 and obtain 1. 
Step 6) 1 is odd; subtract 1 and obtain 0.

Example 2:

Input: num = 8
Output: 4
Explanation: 
Step 1) 8 is even; divide by 2 and obtain 4. 
Step 2) 4 is even; divide by 2 and obtain 2. 
Step 3) 2 is even; divide by 2 and obtain 1. 
Step 4) 1 is odd; subtract 1 and obtain 0.

Example 3:

Input: num = 123
Output: 12

Constraints:

• 0 <= num <= 10^6

解题思路：送分题。

代码如下：

class Solution(object):
    def numberOfSteps (self, num):
        """
        :type num: int
        :rtype: int
        """
        res = 0
        while num > 0:
            res += 1
            if num % 2 == 0:
                num = num / 2
            else:
                num = num - 1
        return res

【leetcode】1342. Number of Steps to Reduce a Number to Zero

标签：def   other   constrain   out   style   代码   output   sub   step   

原文地址：https://www.cnblogs.com/seyjs/p/12287805.html