标签:void value rtt integer mil new com 文件夹 png
宅在家中无事,刷面试题,发现了一个很有意思的面试题。
就来琢磨一下这个是如何能够处理成功。(这是一个长更新视频,说不定中间就干其他的去了,慢慢更ing) StratTime : 202002191600
首先我们来造一下数据。虽然不知道淘宝的购物记录,但是我们来算成ip浏览记录吧。那么我们来获取10亿条ip
代码如下
public class createIp { public static String getRandomIp() { // ip范围 int[][] range = { { 607649792, 608174079 }, // 36.56.0.0-36.63.255.255 { 1038614528, 1039007743 }, // 61.232.0.0-61.237.255.255 { 1783627776, 1784676351 }, // 106.80.0.0-106.95.255.255 { 2035023872, 2035154943 }, // 121.76.0.0-121.77.255.255 { 2078801920, 2079064063 }, // 123.232.0.0-123.235.255.255 { -1950089216, -1948778497 }, // 139.196.0.0-139.215.255.255 { -1425539072, -1425014785 }, // 171.8.0.0-171.15.255.255 { -1236271104, -1235419137 }, // 182.80.0.0-182.92.255.255 { -770113536, -768606209 }, // 210.25.0.0-210.47.255.255 { -569376768, -564133889 }, // 222.16.0.0-222.95.255.255 }; Random rdint = new Random(); int index = rdint.nextInt(10); String ip = num2ip(range[index][0] + new Random().nextInt(range[index][1] - range[index][0])); return ip; } /* * 将十进制转换成IP地址 */ public static String num2ip(int ip) { int[] b = new int[4]; String x = ""; b[0] = (int) ((ip >> 24) & 0xff); b[1] = (int) ((ip >> 16) & 0xff); b[2] = (int) ((ip >> 8) & 0xff); b[3] = (int) (ip & 0xff); x = Integer.toString(b[0]) + "." + Integer.toString(b[1]) + "." + Integer.toString(b[2]) + "." + Integer.toString(b[3]); return x; }
public class topTenValueMake { public static void main(String[] args) throws IOException{ long startTime = System.currentTimeMillis(); int i ; int j ; String strPath = "D:"+File.separator+"test"+File.separator+"TopTenValue.txt"; File file = new File(strPath); file.createNewFile(); FileWriter fWriter = new FileWriter(file); fWriter.write("开始写数据"); for(j=1;j<=100000;j++){ StringBuffer sBuffer = new StringBuffer(); for(i=1;i<=10000;i++){ sBuffer.append(createIp.getRandomIp()+","); } fWriter.write(sBuffer.toString()); fWriter.flush(); System.out.println(j*i); } fWriter.close(); long endTime = System.currentTimeMillis(); long time = endTime - startTime; long hour = time/(60*60*1000); long minute = (time - hour*60*60*1000)/(60*1000); long second = (time - hour*60*60*1000 - minute*60*1000)/1000; System.out.println(hour+ "时" + minute + "分 " + second+"秒"); } }
总运行时间
文件夹大小:
标签:void value rtt integer mil new com 文件夹 png
原文地址:https://www.cnblogs.com/xiaosisong/p/12331750.html