标签:ble turn set clu lse cstring tor 要求 mat
题意:按x从小到大给出n个点,要求一条从最左走到最右再回到最左的路径最小值 要求走过每个点
Solution by Rujia,liu
#include<iostream> #include<string> #include<cmath> #include<cstring> #include<vector> #include<map> #include<set> #include<algorithm> #include<queue> #include<stack> #include<list> #include<sstream> #include<cstdio> #define INF 0x3f3f3f3f //const int maxn = 1e6 + 5; const double PI = acos(-1.0); typedef long long ll; typedef unsigned long long ull; using namespace std; const int maxn = 50 + 5; double x[maxn], y[maxn], dist[maxn][maxn], d[maxn][maxn]; int main() { int n; while (scanf("%d", &n) != EOF) { for (int i = 1; i <= n; i++) scanf("%lf%lf", &x[i], &y[i]); for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) dist[i][j] = sqrt((x[i] - x[j]) * (x[i] - x[j]) + (y[i] - y[j]) * (y[i] - y[j])); } for (int i = n - 1; i >= 2; i--) { for (int j = 1; j < i; j++) { if (i == n - 1) d[i][j] = dist[i][n] + dist[j][n]; else d[i][j] = min(dist[i][i + 1] + d[i + 1][j], dist[j][i + 1] + dist[i + 1][i]); } } printf("%.2f\n", dist[1][2] + d[2][1]); } return 0; }
标签:ble turn set clu lse cstring tor 要求 mat
原文地址:https://www.cnblogs.com/hznumqf/p/12336283.html