复杂链表的复制

 1 /*
 2 public class RandomListNode {
 3     int label;
 4     RandomListNode next = null;
 5     RandomListNode random = null;
 6 
 7     RandomListNode(int label) {
 8         this.label = label;
 9     }
10 }
11 */
12 public class Solution {
13     public RandomListNode Clone(RandomListNode pHead)
14     {
15         if (pHead == null) return null;
16        
17         RandomListNode p, p1 = pHead;
18         
19         RandomListNode nextNode;
20         while (p1 != null) {
21             nextNode = p1.next;
22             p1.next = new RandomListNode(p1.label);
23             p1.next.next = nextNode;
24             p1 = nextNode;
25         }
26         
27         
28         p1 = pHead;
29         while (p1 != null) {
30             if (p1.random != null)
31                 p1.next.random = p1.random.next;
32             p1 = p1.next;
33             p1 = p1.next;
34         }
35         
36         RandomListNode head = pHead.next;
37         p = pHead.next;
38         p1 = pHead;
39         while (p.next != null) {
40             p1.next = p1.next.next;
41             p.next = p.next.next;
42             p = p.next;
43             p1 = p1.next;
44             
45         }
46         p1.next = null;
47         return head;
48     }
49 }