1057 数零壹

#include<iostream>
#include<cctype>
using namespace std;

string str;
int main() {
    getline(cin,str);
    int sum = 0,r ,cnt0 = 0,cnt1 = 0;
    for(int i = 0; i < str.size(); ++i) {
        if(isalpha(str[i])) {
            str[i] = tolower(str[i]);
            sum += str[i]-‘a‘+1;
        }
    }
    while(sum > 0){//在十进制数转二进制数过程中，统计0,1的个数
        r = sum%2;
        if(r == 0) cnt0++;
        else cnt1++;
        sum /= 2;
    }
    printf("%d %d",cnt0,cnt1);
    return 0;
}