标签:des style blog io color ar for sp div
Given a singly linked list L: L0→L1→…→Ln-1→Ln,
reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→…
You must do this in-place without altering the nodes‘ values.
For example,
Given {1,2,3,4}
, reorder it to {1,4,2,3}
.
思路:找到中间节点,将链表的后半部分就地逆置。然后插入到前半部分。
时间复杂度O(n),空间复杂度O(1) 1 /**
2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 void reorderList(ListNode *head) { 12 if (head == NULL || head->next == NULL || head->next->next == NULL) 13 return; 14 15 int length = 0; 16 for (ListNode *pter = head; pter != NULL; pter = pter->next) { 17 ++length; 18 } 19 20 int half_length = 1; 21 ListNode *half = head; 22 while (half_length < (length / 2)) { 23 ++half_length; 24 half = half->next; 25 } 26 27 //reverse 28 ListNode *pter = half->next; 29 half->next = NULL; 30 while (pter != NULL) { 31 ListNode *next_node = pter->next; 32 pter->next = half->next; 33 half->next = pter; 34 pter = next_node; 35 } 36
37 ListNode *pter2 = head; 38 pter = half->next; 39 while (pter2 != half) { 40 ListNode *next_node = pter->next; 41 half->next =next_node; 42 pter->next = pter2->next; 43 pter2->next = pter; 44 pter2 = pter2->next->next; 45 pter = next_node; 46 } 47 } 48 };
标签:des style blog io color ar for sp div
原文地址:http://www.cnblogs.com/vincently/p/4073442.html