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LeetCode 1056. Confusing Number

时间:2020-02-29 13:10:38      阅读:42      评论:0      收藏:0      [点我收藏+]

标签:number   tin   invalid   upload   win   lse   following   this   tps   

原题链接在这里:https://leetcode.com/problems/confusing-number/

题目:

Given a number N, return true if and only if it is a confusing number, which satisfies the following condition:

We can rotate digits by 180 degrees to form new digits. When 0, 1, 6, 8, 9 are rotated 180 degrees, they become 0, 1, 9, 8, 6 respectively. When 2, 3, 4, 5 and 7 are rotated 180 degrees, they become invalid. A confusing number is a number that when rotated 180 degrees becomes a different number with each digit valid.

Example 1:

技术图片

Input: 6
Output: true
Explanation: 
We get 9 after rotating 6, 9 is a valid number and 9!=6.

Example 2:

技术图片

Input: 89
Output: true
Explanation: 
We get 68 after rotating 89, 86 is a valid number and 86!=89.

Example 3:

技术图片

Input: 11
Output: false
Explanation: 
We get 11 after rotating 11, 11 is a valid number but the value remains the same, thus 11 is not a confusing number.

Example 4:

技术图片

Input: 25
Output: false
Explanation: 
We get an invalid number after rotating 25.

Note:

  1. 0 <= N <= 10^9
  2. After the rotation we can ignore leading zeros, for example if after rotation we have 0008 then this number is considered as just 8.

题解:

Check the digit from back to front, if it is not 0, 1, 6, 8, 9, then it is not valid.

And accumlate the corresponding number to num, check if num != N.

Time Complexity: O(n). n is digits of N.

Space: O(1).

AC Java:

 1 class Solution {
 2     public boolean confusingNumber(int N) {
 3         HashMap<Integer, Integer> hm = new HashMap<>();
 4         hm.put(0, 0);
 5         hm.put(1, 1);
 6         hm.put(6, 9);
 7         hm.put(9, 6);
 8         hm.put(8, 8);
 9         int cur = 0;
10         int temp = N;
11         
12         while(N > 0){
13             int d = N % 10;
14             if(!hm.containsKey(d)){
15                 return false;
16             }
17             
18             cur = cur * 10 + hm.get(d);
19             N /= 10;
20         }
21         
22         return cur != temp;
23     }
24 }

 

LeetCode 1056. Confusing Number

标签:number   tin   invalid   upload   win   lse   following   this   tps   

原文地址:https://www.cnblogs.com/Dylan-Java-NYC/p/12382311.html

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