计算器 暂时没解决小数问题

 1 import re
 2 
 3 num_one = ‘(98798465*5465+4654-5464*45616846+84654)‘
 4 print(eval(num_one))
 5 
 6 total = 0
 7 print(num_one)
 8 while True:
 9     try:
10         a = re.search(‘\((\-)(\d+)‘, num_one)
11         if a:
12             num_one = num_one.replace(a.group(1), ‘‘, 1)
13             num_one = num_one.replace(‘)‘, ‘‘)
14             num_one = num_one + str(-2 * int(a.group(2))) + ‘)‘
15             print(num_one)
16         first = re.search(‘[*|/]‘, num_one)
17         print(first.group())
18         try:
19             if first.group() == ‘*‘:
20                 num1 = re.findall(‘(\d+)\*(\d+)‘, num_one)
21                 total1 = int(num1[0][0]) * int(num1[0][1])
22                 # total1 = int(num1[0][0]) * int(num1[0][1])
23                 total += total1
24                 num_one = re.sub(‘\d+\*\d+‘, str(total1), num_one, 1)
25                 print(num_one, ‘11111‘)
26             elif first.group() == ‘/‘:
27                 num1 = re.findall(‘(\d+)/(\d+)‘, num_one)
28                 total1 = int(num1[0][0]) / int(num1[0][1])
29                 total += total1
30                 num_one = re.sub(‘\d+\/\d+‘, str(total1), num_one, 1)
31                 print(num_one)
32         except Exception as f:
33             break
34     except Exception as d:
35         break
36 while True:
37     try:
38         first = re.search(‘\d+([+|-])‘, num_one)
39         print(first.group(1))
40         try:
41             if first.group(1) == ‘+‘:
42                 num1 = re.findall(‘(\d+)\+(\d+)‘, num_one)
43                 total1 = int(num1[0][0]) + int(num1[0][1])
44                 # total1 = int(num1[0][0]) * int(num1[0][1])
45                 total += total1
46                 num_one = re.sub(‘\d+\+\d+‘, str(total1), num_one, 1)
47                 print(num_one, ‘222222‘)
48             elif first.group(1) == ‘-‘:
49                 num1 = re.findall(‘(\d+)\-(\d+)‘, num_one)
50                 total1 = int(num1[0][0]) - int(num1[0][1])
51                 total += total1
52                 if total1 < 0 and len(re.findall(‘\d+‘, num_one)) > 2:
53                     num_one = re.sub(‘\d+\-\d+‘, str(abs(total1)), num_one, 1)
54                     num_one = num_one.replace(‘)‘, ‘‘)
55                     num_one = num_one + str(total1 * 2) + ‘)‘
56                 elif total1 < 0 and len(re.findall(‘\d+‘, num_one)) <= 2:
57                     num_one = str(total1)
58                     break
59                 else:
60                     num_one = re.sub(‘\d+\-\d+‘, str(total1), num_one, 1)
61                     print(num_one, ‘33333‘)
62         except Exception as f:
63             break
64     except Exception as d:
65         break
66 num_one = re.sub(‘[()]‘, ‘‘, num_one)
67 print(num_one)
68 输出：
69 290683253989
70 290683253989