标签:long namespace 快速幂取模 std res void out include car
基本思想:
快速幂取模,如果不去模,就是快速幂大数问题;
关键点:
无;
#include<iostream> #include<string> using namespace std; typedef long long ll; string s; //int f[maxn]; void multip(string &s, int n) { int carry = 0; for (int i = 0; i < s.size(); i++) { int temp = carry + (s[i] - ‘0‘)*n; s[i] = temp % 10 + ‘0‘; carry = temp / 10; } while (carry != 0) { s += char(‘0‘ + carry % 10); carry /= 10; } } int charge(int n,int m) { int base = n; int res = 1; while (m != 0) { if (m % 2 !=0) { res = res * base; res %= 1000; } base *= base; base %= 1000; m /= 2; } return res; } int main() { int n, m; while (cin >> n >> m) { if (n == 0 && m == 0) break; cout << charge(n, m) << endl; } return 0; }
杭电ACMOJ 人见人爱A^B Easy *第一次见到快速幂取模
标签:long namespace 快速幂取模 std res void out include car
原文地址:https://www.cnblogs.com/songlinxuan/p/12448136.html